Spring Boot,Hibernate搜索属性

Question

如何在使用Spring Boot时提供Hibernate Search参数？

...
spring.datasource.driverClassName=org.postgresql.Driver

hibernate.search.jmx_enabled=true
hibernate.search.default.directory_provider=filesystem
hibernate.search.generate_statistics=true
hibernate.search.lucene_version=LUCENE_CURRENT
hibernate.search.default.indexBase=/mypath-to-index

它并不关心我提供的内容.始终应用默认设置.

我认为下面的代码没有任何东西来处理与Hibernate Search相关的属性.这可能是问题吗？

https://github.com/spring-projects/spring-boot/blob/master/spring-boot-autoconfigure/src/main/java/org/springframework/boot/autoconfigure/orm/jpa/JpaProperties.java

Answer 1

如果放入"spring.jpa.properties",可以将它们放在application.properties文件中.在物业名称前面.

例:

spring.jpa.properties.hibernate.search.jmx_enabled=true
spring.jpa.properties.hibernate.search.default.directory_provider=filesystem
spring.jpa.properties.hibernate.search.generate_statistics=true
spring.jpa.properties.hibernate.search.lucene_version=LUCENE_CURRENT
spring.jpa.properties.hibernate.search.default.indexBase=/mypath-to-index

Spring将在spring.jpa.properties.*下获取任何属性,并在创建EntityManagerFactory后传递它们(带有前缀剥离).