两天的两个时间戳之间的MySql差异？

Question

如何在几天内获得两个时间戳之间的差异？我应该使用datetime列吗？

---

我将我的专栏改为日期时间.简单的减法似乎不会在几天内给我一个结果.

mysql> SELECT NOW(), last_confirmation_attempt, NOW() - last_confirmation_attempt AS diff  FROM DateClubs HAVING diff IS NOT NULL ;
+---------------------+---------------------------+-----------------+
| NOW()               | last_confirmation_attempt | diff            |
+---------------------+---------------------------+-----------------+
| 2010-03-30 10:52:31 | 2010-03-16 10:41:47       | 14001084.000000 |
+---------------------+---------------------------+-----------------+
1 row in set (0.00 sec)

我不认为diff是在几秒钟内,因为当我diff在一天中除以秒数(86,400)时,我得不到一个明智的答案:

mysql> SELECT NOW(), last_confirmation_attempt, ( NOW() - last_confirmation_attempt) / 86400 AS diff  FROM DateClubs HAVING diff IS NOT NULL ;
+---------------------+---------------------------+----------------+
| NOW()               | last_confirmation_attempt | diff           |
+---------------------+---------------------------+----------------+
| 2010-03-30 10:58:58 | 2010-03-16 10:41:47       | 162.0568402778 |
+---------------------+---------------------------+----------------+
1 row in set (0.00 sec)

Answer 1

如果您乐意忽略列中的时间部分,DATEDIFF()将为您提供几天内您所寻找的差异.

SELECT DATEDIFF('2010-10-08 18:23:13', '2010-09-21 21:40:36') AS days;
+------+
| days |
+------+
|   17 |
+------+

Answer 2

我知道已经很老了,但我只是为了它而说 - 我正在寻找同样的问题而且到了这里,但我需要天数的差异.

我使用SELECT (UNIX_TIMESTAMP(DATE1) - UNIX_TIMESTAMP(DATE2))/60/60/24 Unix_timestamp返回以秒为单位的差异,然后我只分为分钟(秒/ 60),小时(分钟/ 60),天(小时/ 24).

Answer 3

如果你想以完整的TIMESTAMP格式返回而不是尝试: -

 SELECT TIMEDIFF(`call_end_time`, `call_start_time`) as diff from tablename;

回来就像

     diff
     - - -
    00:05:15

Answer 4

CREATE TABLE t (d1 timestamp, d2 timestamp);

INSERT INTO t VALUES ('2010-03-11 12:00:00', '2010-03-30 05:00:00');
INSERT INTO t VALUES ('2010-03-11 12:00:00', '2010-03-30 13:00:00');
INSERT INTO t VALUES ('2010-03-11 00:00:00', '2010-03-30 13:00:00');
INSERT INTO t VALUES ('2010-03-10 12:00:00', '2010-03-30 13:00:00');
INSERT INTO t VALUES ('2010-03-10 12:00:00', '2010-04-01 13:00:00');

SELECT d2, d1, DATEDIFF(d2, d1) AS diff FROM t;

+---------------------+---------------------+------+
| d2                  | d1                  | diff |
+---------------------+---------------------+------+
| 2010-03-30 05:00:00 | 2010-03-11 12:00:00 |   19 |
| 2010-03-30 13:00:00 | 2010-03-11 12:00:00 |   19 |
| 2010-03-30 13:00:00 | 2010-03-11 00:00:00 |   19 |
| 2010-03-30 13:00:00 | 2010-03-10 12:00:00 |   20 |
| 2010-04-01 13:00:00 | 2010-03-10 12:00:00 |   22 |
+---------------------+---------------------+------+
5 rows in set (0.00 sec)

Answer 5

如果您需要计算到第二个的天数差异：

SELECT TIMESTAMPDIFF(SECOND,'2010-09-21 21:40:36','2010-10-08 18:23:13')/86400 AS diff

它会回来
diff
16.8629