Pie*_*NAY 72 mysql range overlapping-matches
该表用于存储会话(事件):
CREATE TABLE session (
id int(11) NOT NULL AUTO_INCREMENT
, start_date date
, end_date date
);
INSERT INTO session
(start_date, end_date)
VALUES
("2010-01-01", "2010-01-10")
, ("2010-01-20", "2010-01-30")
, ("2010-02-01", "2010-02-15")
;
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我们不希望范围之间发生冲突.
假设我们需要在2010-01-05到2010-01-25之间插入一个新会话.
我们想知道冲突的会话.
这是我的查询:
SELECT *
FROM session
WHERE "2010-01-05" BETWEEN start_date AND end_date
OR "2010-01-25" BETWEEN start_date AND end_date
OR "2010-01-05" >= start_date AND "2010-01-25" <= end_date
;
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结果如下:
+----+------------+------------+
| id | start_date | end_date |
+----+------------+------------+
| 1 | 2010-01-01 | 2010-01-10 |
| 2 | 2010-01-20 | 2010-01-30 |
+----+------------+------------+
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有没有更好的方法来实现这一目标?
sou*_*rge 138
我曾经用我曾经写过的日历应用程序进行了这样的查询.我想我用过这样的东西:
... WHERE new_start < existing_end
AND new_end > existing_start;
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更新这绝对有用((ns,ne,es,ee)=(new_start,new_end,existing_start,existing_end)):
这是一个小提琴
Lam*_*amy 27
SELECT * FROM tbl WHERE
existing_start BETWEEN $newStart AND $newEnd OR
existing_end BETWEEN $newStart AND $newEnd OR
$newStart BETWEEN existing_start AND existing_end
if (!empty($result))
throw new Exception('We have overlapping')
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这3行sql子句涵盖了4个需要重叠的情况.
小智 13
拉米的答案很好,但你可以多一点优化它.
SELECT * FROM tbl WHERE
existing_start BETWEEN $newSTart AND $newEnd OR
$newStart BETWEEN existing_start AND existing_end
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这将捕获范围重叠的所有四种情况,并排除它们不重复的两种情况.
我也遇到过类似的问题。我的问题是在一系列封锁日期之间停止预订。例如,5 月 2 日至 7 日期间的酒店预订将被阻止。我需要找到任何类型的重叠日期来检测并停止预订。我的解决方案类似于LordJavac。
SELECT * FROM ib_master_blocked_dates WHERE venue_id=$venue_id AND
(
(mbd_from_date BETWEEN '$from_date' AND '$to_date')
OR
(mbd_to_date BETWEEN '$from_date' AND '$to_date')
OR
('$from_date' BETWEEN mbd_from_date AND mbd_to_date)
OR
('$to_date' BETWEEN mbd_from_date AND mbd_to_date)
)
*mbd=master_blocked_dates
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如果不起作用请告诉我。