Fra*_*sta 11 javascript random algorithm
我需要生成两个不同的随机数,它们不能彼此相等或与第三个数相等.我尝试使用很多if来涵盖所有可能性但是,似乎我的算法技能并不那么好.
谁可以帮我这个事?
var numberOne = Math.floor(Math.random() * 4);
var numberTwo = Math.floor(Math.random() * 4);
var numberThree = 3; // This number will not always be 3
if((numberOne == numberThree) && (numberOne + 1 < 3)) {
numberOne++;
} else if ((numberOne == numberThree) && (numberOne + 1 == 3)) {
numberOne = 0;
}
if ((numberOne == numberTwo) && (numberOne+1 < 3)) {
if (numberOne+1 < 3) {
numberOne++;
} else if(numberThree != 0) {
numberOne = 0;
}
}
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这是我到目前为止,下一步将是:
if (numberTwo == numberThree) {
(...)
}
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我的思路是否正确?注意:生成的数字需要介于0和3之间.提前感谢.
您可以运行while循环,直到所有数字都不同.
// All numbers are equal
var numberOne = 3;
var numberTwo = 3;
var numberThree = 3;
// run this loop until numberOne is different than numberThree
do {
numberOne = Math.floor(Math.random() * 4);
} while(numberOne === numberThree);
// run this loop until numberTwo is different than numberThree and numberOne
do {
numberTwo = Math.floor(Math.random() * 4);
} while(numberTwo === numberThree || numberTwo === numberOne);
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以下是基于@jfriend00的建议http://jsfiddle.net/x4g4kkwc/1的上述代码的jsfiddle .
这是最初的工作演示:http://jsfiddle.net/x4g4kkwc/