Ste*_*ini 108 python decorator
我需要将例程标记为已弃用,但显然没有标准的库装饰器可供弃用.我知道它的配方和警告模块,但我的问题是:为什么这个(常见)任务没有标准的库装饰器?
附加问题:标准库中是否有标准装饰器?
Pat*_*oni 49
这里有一些片段,根据Leandro引用的片段进行修改:
import warnings
import functools
def deprecated(func):
"""This is a decorator which can be used to mark functions
as deprecated. It will result in a warning being emitted
when the function is used."""
@functools.wraps(func)
def new_func(*args, **kwargs):
warnings.simplefilter('always', DeprecationWarning) # turn off filter
warnings.warn("Call to deprecated function {}.".format(func.__name__),
category=DeprecationWarning,
stacklevel=2)
warnings.simplefilter('default', DeprecationWarning) # reset filter
return func(*args, **kwargs)
return new_func
# Examples
@deprecated
def some_old_function(x, y):
return x + y
class SomeClass:
@deprecated
def some_old_method(self, x, y):
return x + y
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因为在某些解释器中,暴露的第一个解决方案(没有过滤器处理)可能会导致警告抑制.
Lau*_*RTE 34
这是另一个解决方案:
这个装饰器(实际上是一个装饰工厂)允许你给出一个原因信息.通过提供源文件名和行号来帮助开发人员诊断问题也更有用.
编辑:此代码使用Zero的建议:它替换warnings.warn_explicitline by warnings.warn(msg, category=DeprecationWarning, stacklevel=2),它打印函数调用站点而不是函数定义站点.它使调试更容易.
EDIT2:此版本允许开发人员指定可选的"原因"消息.
import functools
import inspect
import warnings
string_types = (type(b''), type(u''))
def deprecated(reason):
"""
This is a decorator which can be used to mark functions
as deprecated. It will result in a warning being emitted
when the function is used.
"""
if isinstance(reason, string_types):
# The @deprecated is used with a 'reason'.
#
# .. code-block:: python
#
# @deprecated("please, use another function")
# def old_function(x, y):
# pass
def decorator(func1):
if inspect.isclass(func1):
fmt1 = "Call to deprecated class {name} ({reason})."
else:
fmt1 = "Call to deprecated function {name} ({reason})."
@functools.wraps(func1)
def new_func1(*args, **kwargs):
warnings.simplefilter('always', DeprecationWarning)
warnings.warn(
fmt1.format(name=func1.__name__, reason=reason),
category=DeprecationWarning,
stacklevel=2
)
warnings.simplefilter('default', DeprecationWarning)
return func1(*args, **kwargs)
return new_func1
return decorator
elif inspect.isclass(reason) or inspect.isfunction(reason):
# The @deprecated is used without any 'reason'.
#
# .. code-block:: python
#
# @deprecated
# def old_function(x, y):
# pass
func2 = reason
if inspect.isclass(func2):
fmt2 = "Call to deprecated class {name}."
else:
fmt2 = "Call to deprecated function {name}."
@functools.wraps(func2)
def new_func2(*args, **kwargs):
warnings.simplefilter('always', DeprecationWarning)
warnings.warn(
fmt2.format(name=func2.__name__),
category=DeprecationWarning,
stacklevel=2
)
warnings.simplefilter('default', DeprecationWarning)
return func2(*args, **kwargs)
return new_func2
else:
raise TypeError(repr(type(reason)))
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您可以将此装饰器用于函数,方法和类.
这是一个简单的例子:
@deprecated("use another function")
def some_old_function(x, y):
return x + y
class SomeClass(object):
@deprecated("use another method")
def some_old_method(self, x, y):
return x + y
@deprecated("use another class")
class SomeOldClass(object):
pass
some_old_function(5, 3)
SomeClass().some_old_method(8, 9)
SomeOldClass()
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你会得到:
deprecated_example.py:59: DeprecationWarning: Call to deprecated function or method some_old_function (use another function).
some_old_function(5, 3)
deprecated_example.py:60: DeprecationWarning: Call to deprecated function or method some_old_method (use another method).
SomeClass().some_old_method(8, 9)
deprecated_example.py:61: DeprecationWarning: Call to deprecated class SomeOldClass (use another class).
SomeOldClass()
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EDIT3:这个装饰器现在是Deprecated库的一部分:
新的稳定版本v1.2.4
jha*_*805 16
未来的 Python 版本(3.12 之后)将包含warnings.deprecated装饰器,该装饰器将指示弃用类型检查器,例如mypy.
作为一个例子,考虑这个名为library.pyi的库存根:
Run Code Online (Sandbox Code Playgroud)from warnings import deprecated @deprecated("Use Spam instead") class Ham: ... @deprecated("It is pining for the fiords") def norwegian_blue(x: int) -> int: ... @overload @deprecated("Only str will be allowed") def foo(x: int) -> str: ... @overload def foo(x: str) -> str: ...以下是类型检查器应如何处理该库的使用:
Run Code Online (Sandbox Code Playgroud)from library import Ham # error: Use of deprecated class Ham. Use Spam instead. import library library.norwegian_blue(1) # error: Use of deprecated function norwegian_blue. It is pining for the fiords. map(library.norwegian_blue, [1, 2, 3]) # error: Use of deprecated function norwegian_blue. It is pining for the fiords. library.foo(1) # error: Use of deprecated overload for foo. Only str will be allowed. library.foo("x") # no error ham = Ham() # no error (already reported above)来源:PEP702
如muon所建议,您可以deprecation为此安装软件包。
该
deprecation库为您的测试提供了一个deprecated装饰器和一个fail_if_not_removed装饰器。
pip install deprecation
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import deprecation
@deprecation.deprecated(deprecated_in="1.0", removed_in="2.0",
current_version=__version__,
details="Use the bar function instead")
def foo():
"""Do some stuff"""
return 1
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有关完整文档,请参见http://deprecation.readthedocs.io/。
我想原因是Python代码不能静态处理(就像它对C++编译器所做的那样),在实际使用之前你不能得到关于使用某些东西的警告.我不认为用一堆消息向您的脚本用户发送垃圾邮件是"好主意""警告:此脚本的开发人员正在使用已弃用的API".
更新:但您可以创建装饰器,将原始功能转换为另一个.新功能将标记/检查开关,告知该功能已被调用,并且仅在转换为开启状态时显示消息.和/或在退出时,它可以打印程序中使用的所有已弃用函数的列表.
您可以创建一个utils文件
import warnings
def deprecated(message):
def deprecated_decorator(func):
def deprecated_func(*args, **kwargs):
warnings.warn("{} is a deprecated function. {}".format(func.__name__, message),
category=DeprecationWarning,
stacklevel=2)
warnings.simplefilter('default', DeprecationWarning)
return func(*args, **kwargs)
return deprecated_func
return deprecated_decorator
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然后导入弃用装饰器,如下所示:
from .utils import deprecated
@deprecated("Use method yyy instead")
def some_method()"
pass
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