UIApplication openUrl不使用格式化的NSString

Question

我有以下代码打开谷歌地图:

NSString *urlString = [NSString stringWithFormat:@"http://maps.google.com/maps?q=%@, Anchorage, AK",addressString];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:urlString]];

但它不起作用,没有错误.它只是没有打开.

Answer 1

URLWithString需要一个百分比转义字符串.您的示例网址包含空格,导致创建无NSURL.此外,addressString还可能包含需要转义的字符.首先尝试使用百分比转义url字符串:

NSString *urlString = [NSString stringWithFormat:@"http://maps.google.com/maps?q=%@, Anchorage, AK",addressString];
NSString *escaped = [urlString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:escaped]];  

Answer 2

需要转义urlString,否则[NSURL URLWithString:urlString]将返回nill.

NSString *urlString = [NSString stringWithFormat:@"http://maps.google.com/maps?q=%@, Anchorage, AK",addressString];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:[urlString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding] ]];