我尝试使用snprintf将一些数字转换为字符串.name1在逗号后应与name2具有相同的数字.
#include <stdio.h>
#define length 50
int main()
{
char name1 [length];
char name2 [length];
double step= 0.00001;
unsigned long long int iterMax =100000000000;
int k;
for (k = 0; k <= 20; k++)
{ printf("numbers : k = %2d ; k*step = %f ;", k, k*step);
snprintf(name1,length+1,"%f", iterMax+k*step); /* */
snprintf(name2,length+1, " %f", k*step); /* */
printf("strings : k*step = %s ; iterMax+k*step = %s \n",name2, name1);
}
return 0;
}
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编译它:
gcc t.c -Wall
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输出是:
./a.out
numbers : k = 0 ; k*step = 0.000000 ;strings : k*step = 0.000000 ; iterMax+k*step = 100000000000.000000
numbers : k = 1 ; k*step = 0.000010 ;strings : k*step = 0.000010 ; iterMax+k*step = 100000000000.000015
numbers : k = 2 ; k*step = 0.000020 ;strings : k*step = 0.000020 ; iterMax+k*step = 100000000000.000015
numbers : k = 3 ; k*step = 0.000030 ;strings : k*step = 0.000030 ; iterMax+k*step = 100000000000.000031
numbers : k = 4 ; k*step = 0.000040 ;strings : k*step = 0.000040 ; iterMax+k*step = 100000000000.000046
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当iterMax较小时,结果是相同的(数字aftter逗号),例如100000000:
numbers : k = 0 ; k*step = 0.000000 ;strings : k*step = 0.000000 ; iterMax+k*step = 100000000.000000
numbers : k = 1 ; k*step = 0.000010 ;strings : k*step = 0.000010 ; iterMax+k*step = 100000000.000010
numbers : k = 2 ; k*step = 0.000020 ;strings : k*step = 0.000020 ; iterMax+k*step = 100000000.000020
numbers : k = 3 ; k*step = 0.000030 ;strings : k*step = 0.000030 ; iterMax+k*step = 100000000.000030
numbers : k = 4 ; k*step = 0.000040 ;strings : k*step = 0.000040 ; iterMax+k*step = 100000000.000040
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ULLONG_MAX = 18446744073709551615比iterMax大.
我怎么解决这个问题?
TIA
这实际上是一个double精确的问题.还有很多其他问题可以解释更多有关IEEE-754浮点数的问题,但我将在此总结相关要点:
double和家庭有效地以科学记数法存储数字,精度有限.这意味着数字越大,它的准确度就越低.0.1不能精确存储(相反,它是类似的0.10000000149011612)因此,数字100000000000.000010是"大",因此在小数位后变得不太准确.事实上,一旦你开始4503599627370496,你甚至不能存储所有整数!