Gad*_*s34 3 c# asp.net-mvc entity-framework
我正在尝试使用ASP.NET Identity 2.0启动并运行MVC 5项目.我的出发点是本教程中的示例应用程序.我的初始页面是Home/Index.当我尝试进行搜索(期望返回值为null)时,应用程序只会挂起,我无法弄清楚原因.db上下文的实例化导致调用Seed()方法,这似乎正常,但它挂起在roleManager.FindByName(roleName)调用上(我在下面的代码中对它进行了评论).暂停调试器显示它被卡住但我不知道从那里去哪里.相关课程如下.
控制器:
public class HomeController : ApplicationController
{
public ActionResult Index()
{
var user = db.Users.Find("dummyVal");
return View();
}
[Authorize]
public ActionResult About()
{
ViewBag.Message = "Your app description page.";
return View();
}
public ActionResult Contact()
{
ViewBag.Message = "Your contact page.";
return View();
}
}
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基础控制器:
public abstract class ApplicationController : Controller
{
protected ApplicationDbContext db;
public ApplicationController()
{
db = new ApplicationDbContext();
}
}
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DB初始化器:
public class ApplicationDbInitializer : DropCreateDatabaseAlways<ApplicationDbContext>
{
protected override void Seed(ApplicationDbContext context) {
InitializeIdentityForEF(context);
base.Seed(context);
}
//Create User=Admin@Admin.com with password=Admin@123456 in the Admin role
public static void InitializeIdentityForEF(ApplicationDbContext db) {
var userManager = HttpContext.Current.GetOwinContext().GetUserManager<ApplicationUserManager>();
var roleManager = HttpContext.Current.GetOwinContext().Get<ApplicationRoleManager>();
const string name = "admin@example.com";
const string password = "Admin@123456";
const string roleName = "Admin";
//Create Role Admin if it does not exist
// EXECUTION HANGS ON THIS CALL...
var role = roleManager.FindByName(roleName);
if (role == null) {
role = new IdentityRole(roleName);
var roleresult = roleManager.Create(role);
}
var user = userManager.FindByName(name);
if (user == null) {
user = new ApplicationUser { UserName = name, Email = name };
var result = userManager.Create(user, password);
result = userManager.SetLockoutEnabled(user.Id, false);
}
// Add user admin to Role Admin if not already added
var rolesForUser = userManager.GetRoles(user.Id);
if (!rolesForUser.Contains(role.Name)) {
var result = userManager.AddToRole(user.Id, role.Name);
}
// Create dummy user
const string dummyUserName = "PeterVenkman";
const string dummyUserPwd = "gf%^^ftf83X";
var dummyUser = userManager.FindByName(dummyUserName);
if (dummyUser == null) {
dummyUser = new ApplicationUser { UserName = dummyUserName, Email = dummyUserName };
var result = userManager.Create(dummyUser, dummyUserPwd);
result = userManager.SetLockoutEnabled(dummyUser.Id, false);
}
}
}
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Suh*_*shi 13
该错误是因为您在控制器中实例化dbContext对象而不是从owin上下文中获取它.控制器中存在两个不同的上下文对象,而同一个数据库中的启动中存在一个上下文对象导致此死锁.解决此问题的最简单方法是替换代码
db = new ApplicationDbContext();
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同
db = System.Web.HttpContext.Current.GetOwinContext().Get<ApplicationDbContext>();
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解决了这个问题
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