我有一个字典列表,如下所示:
l = [{'name': 'john', 'amount': 50}, {'name': 'al', 'amount': 20}, {'name': 'john', 'amount': 80}]
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有没有办法组合/合并匹配的名称值字典和总和金额?
您可以使用collections.Counter()对象将名称映射到金额,并在进行时对它们求和:
from collections import Counter
summed = Counter()
for d in l:
summed[d['name']] += d['amount']
result = [{'name': name, 'amount': amount} for name, amount in summed.most_common()]
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然后结果也按数量排序(最高的第一个):
>>> from collections import Counter
>>> l = [{'name': 'john', 'amount': 50}, {'name': 'al', 'amount': 20}, {'name': 'john', 'amount': 80}]
>>> summed = Counter()
>>> for d in l:
... summed[d['name']] += d['amount']
...
>>> summed
Counter({'john': 130, 'al': 20})
>>> [{'name': name, 'amount': amount} for name, amount in summed.most_common()]
[{'amount': 130, 'name': 'john'}, {'amount': 20, 'name': 'al'}]
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