Rob*_*rby 1 php mysql ajax jquery codeigniter
我有一个AJAX脚本,应该在用户登录时将数据插入到mysql数据库中.但是它当前正在运行success函数,即使在控制台中返回'success'=>'false'时也是如此.
她是我的代码
$(document).ready(function() {
$("#addfav").click(function() {
var form_data = {heading: $("#vidheading").text(), embed : $("#vidembed").text()};
jQuery.ajax({
type:"POST",
url:"http://localhost/stumble/Site/add_to_fav",
dataType: "json",
data: form_data,
success: function (data){
alert("This Video Has Been Added To Your Favourites");
console.log(data.status);
},
error: function (data){
if(data.success == false){
alert("You Must Be Logged In to Do That");
console.log(data.status);
};
}
});
})
})
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这是php,请记住我的项目是在codeigniter中.
public function add_to_fav(){
header('Content-Type: application/json');
$this->load->model('model_users');
$this->model_users->add_favs();
}
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这是向db添加数据的实际模型
public function add_favs(){
if($this->session->userdata('username')){
$data = array(
'username' => $this->session->userdata('username'),
'title' => $this->input->post('heading'),
'embed' => $this->input->post('embed')
);
$query = $this->db->insert('fav_videos',$data);
echo json_encode(array('success'=>'true'));
} else {
echo json_encode(array('success'=>'false'));
}
}
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谢谢你的任何建议!