检测单击操作栏的"溢出"菜单按钮

Question

我可以检测操作栏菜单按钮上的点击/点击,即用于显示溢出菜单项吗？

默认情况下,它会打开列表,其中包含一个"设置"项.这是截图:

到目前为止它正在检测点击"2",但我想检测点击"1".

Answer 1

要检测溢出菜单上的单击,请输入以下代码:

@Override
public boolean onMenuOpened(int featureId, Menu menu) {
    if(featureId == AppCompatDelegate.FEATURE_SUPPORT_ACTION_BAR && menu != null){
        //overflow menu clicked, put code here...
    }
    return super.onMenuOpened(featureId, menu);
}

@Override
public void onPanelClosed(int featureId, Menu menu) {
    ...
}

要检测单击菜单项,以防您有这样的菜单:

<?xml version="1.0" encoding="utf-8"?>
<menu xmlns:android="http://schemas.android.com/apk/res/android">
    <item android:id="@+id/menu2" android:alphabeticShortcut="b"
        android:title="Menu No. 2" android:orderInCategory="2">
        <menu >
        <group android:id="@+id/group2" android:checkableBehavior="single">
            <item android:id="@+id/submenu1" android:title="SubMenu No. 1" />
            <item android:id="@+id/submenu2" android:title="SubMenu No. 2" />
        </group>  
        </menu>
    </item>
</menu>

您应该能够检测到点击

onOptionsItemSelected

@Override
public boolean onOptionsItemSelected(MenuItem item) {

    Log.w("ANDROID MENU TUTORIAL:", "onOptionsItemSelected(MenuItem item)");

    // Handle item selection
    switch (item.getItemId()) {
    case R.id.menu2:
        Toast.makeText(this, "Clicked: Menu No. 2", Toast.LENGTH_SHORT).show();
        return true;   
        ...
}

Answer 2

最后我找到了解决方案。覆盖 FragmentActivity.onKeyDown

@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
    // TODO Auto-generated method stub
    switch (keyCode) {

    case KeyEvent.KEYCODE_MENU:
        // Do Sometihng
        break;

    default:
        break;
    }
    return super.onKeyDown(keyCode, event);
}