只读模式下不允许写操作 - 持久时发出

Question

尝试将对象保存到数据库时,我一直面临以下错误.我试过这里提到的解决方案1和here2但没有好处.我正在学习一个教程,但唯一的区别是Spring和Hibernate的版本.

我能够使用SessionFactory直接持久化对象,但如果我使用HibernateDaoSupport尝试此操作,它会失败并出现以下错误

spring.xml

<bean id="dataSource" class="org.apache.commons.dbcp2.BasicDataSource">
    <property name="driverClassName" value="oracle.jdbc.driver.OracleDriver" />
    <property name="url" value="jdbc:oracle:thin:@localhost:1521:xe" />
    <property name="username" value="system" />
    <property name="password" value="xxx" />
</bean>

<context:annotation-config/>

<bean id="sessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
    <property name="dataSource" ref="dataSource"></property>
    <property name="packagesToScan" value="org.sri.sphiber.model"></property>
    <property name="hibernateProperties">
        <props>
            <prop key="dialect">org.hibernate.dialect.OracleDialect</prop>
            <prop key="hibernate.hbm2ddl.auto">update</prop>
            <prop key="hibernate.show_sql">true</prop>
        </props>
    </property>
</bean>



<bean id="customerDAOImpl" class="org.sri.sphiber.dao.CustomerDAOImpl">
    <property name="hibernateTemplate" ref="hibernateTemplate" />
</bean>

<bean id="hibernateTemplate" class="org.springframework.orm.hibernate4.HibernateTemplate">
    <property name="sessionFactory" ref="sessionFactory" />
</bean>

<bean id="txManager" class="org.springframework.orm.hibernate4.HibernateTransactionManager"> 
    <property name="sessionFactory" ref="sessionFactory" /> 
</bean> 

CustomerDAOImpl.java

public class CustomerDAOImpl extends HibernateDaoSupport {

    public boolean insertCustomer(Customer cust){

        try {
            getHibernateTemplate().saveOrUpdate(cust);
        } catch (DataAccessException e) {
            e.printStackTrace();
            return false;
        }
        return true;
    }

}

使用调用它.

public class MainClass {

    public static void main(String[] args) {


            ApplicationContext appContext = new ClassPathXmlApplicationContext("spring.xml");
            CustomerDAOImpl hdi=appContext.getBean("customerDAOImpl",CustomerDAOImpl.class);


            Customer customer=new Customer();
            customer.setCustomerName("Sri");

            boolean isUpdated = hdi.insertCustomer(customer);

    }


}

错误信息.

Aug 10, 2014 12:45:52 AM org.hibernate.tool.hbm2ddl.SchemaUpdate execute
INFO: HHH000232: Schema update complete
org.springframework.dao.InvalidDataAccessApiUsageException: Write operations are not allowed in read-only mode (FlushMode.MANUAL): Turn your Session into FlushMode.COMMIT/AUTO or remove 'readOnly' marker from transaction definition.
    at org.springframework.orm.hibernate4.HibernateTemplate.checkWriteOperationAllowed(HibernateTemplate.java:1135)
    at org.springframework.orm.hibernate4.HibernateTemplate$16.doInHibernate(HibernateTemplate.java:684)
    at org.springframework.orm.hibernate4.HibernateTemplate.doExecute(HibernateTemplate.java:340)
    at org.springframework.orm.hibernate4.HibernateTemplate.executeWithNativeSession(HibernateTemplate.java:308)
    at org.springframework.orm.hibernate4.HibernateTemplate.saveOrUpdate(HibernateTemplate.java:681)
    at org.sri.sphiber.dao.CustomerDAOImpl.insertCustomer(CustomerDAOImpl.java:16)
    at org.sri.sphiber.main.MainClass.main(MainClass.java:26)

版本细节:

Spring version : spring-framework-4.0.6.RELEASE
Hibernate Version : hibernate-release-4.3.5.Final
Database : Orcale 11g

Answer 1

您缺少TransactionManager定义,请参阅http://docs.spring.io/spring-framework/docs/current/spring-framework-reference/html/transaction.html

[更新]以前我是从我的手机写的,所以很难提供细节,这是你需要做的:

1. Spring xml配置:
   

   <tx:annotation-driven/>
   <bean id="transactionManager" class="org.springframework.orm.hibernate4.HibernateTransactionManager"> 
   <property name="sessionFactory" ref="sessionFactory" /> 
   </bean> 
   

2. 将@Transactional注释添加到CustomerDaoImpl.insertCustomer方法

现在你的代码应该工作了.

请注意 @Transactional注释应该在服务层中使用,而不是像在这个例子中那样在DAO层中使用.
@Transactional注释告诉spring创建使用方面"包装"带有事务的事务的注释方法的代理.