eas*_*syX 4 javascript angularjs angularjs-ng-repeat
我有数据"喜欢"这个:
$scope.persons = {
"ID123": {
name_de: "Andre",
name_en: "Anrew",
age: 30,
description: "He is the father of xyz and . . .",
. . .
},
"IDabc": {
name_de: "Markus",
name_en: "Mark",
age: 20,
. . .
},
"IDxyz": {
name_de: "Isaak",
name_en: "Isaac",
age: 23,
. . .
}
. . .
}
Run Code Online (Sandbox Code Playgroud)
我有一个输入/ ng-repeat:
<input ng-model="query" placeholder="Suche . . .">
<ul>
<li ng-repeat="p in persons | orderBy:'name_de' | filter:query"> Some output here . . . </li>
</ul>
Run Code Online (Sandbox Code Playgroud)
现在问题是如何订购和过滤这个?
它与一群人合作,但我需要"ID",所以对象是必要的!?
我正在寻找一种通过N属性过滤对象的方法,例如对于name_de和name_en(如果我搜索安德烈,如果我搜索安德鲁,它将显示ID123)但忽略"描述"的文本(第一个我有过滤器检查所有属性的问题)
你可以使用toArrayfilter模块更多信息,请看这里:http://ngmodules.org/modules/angular-toArrayFilter
并为您的解决方案提供示例演示http://jsbin.com/nimoxa/1/edit JS:
angular.module('angular-toArrayFilter', [])
.filter('toArray', function () {
return function (obj, addKey) {
if (!(obj instanceof Object)) {
return obj;
}
if ( addKey === false ) {
return Object.values(obj);
} else {
return Object.keys(obj).map(function (key) {
return Object.defineProperty(obj[key], '$key', { enumerable: false, value: key});
});
}
};
});
var app = angular.module('app', ['angular-toArrayFilter']);
app.controller('firstCtrl', function($scope){
$scope.persons = {
"IDabc": {
name_de: "Markus",
name_en: "Mark",
age: 20,
},
"ID123": {
name_de: "Andre",
name_en: "Anrew",
age: 30,
description: "He is the father of xyz and . . .",
},
"IDxyz": {
name_de: "Isaak",
name_en: "Isaac",
age: 23,
}
};
});
Run Code Online (Sandbox Code Playgroud)
HTML:
body ng-app="app">
<div ng-controller="firstCtrl">
<input ng-model="query" placeholder="Suche . . .">
<ul>
<li ng-repeat="p in persons | toArray | orderBy:'age' | filter:query"> {{p.name_de}} -> {{p.name_en}} </li>
</ul>
</div>
</body>
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
21964 次 |
| 最近记录: |