无法获取要执行的PDO删除语句

Question

我无法获取表单发布变量,然后让我的PDO语句执行删除.我知道变量$得到的[WID]确实在我的表单中存储了正确的值.问题在于将变量从这个表单传递给下面的代码来执行delete语句.我得到的错误是:参数号无效:参数未定义

//这里是php/PDO代码:

 if(isset($_POST['remove'])){
 $the_WID = $_POST['WID'];
 echo "here is the WID" . $the_WID;

 $dlt = "DELETE FROM writing WHERE writing.WID = :writing.WID";
 $stmtdlt = $dbh->prepare($dlt);
 $stmtdlt->bindParam(':writing.WID', $the_WID, PDO::PARAM_INT);                                           
 $stmtdlt->execute(); 
 }

//这是表格

<form action="" method="post">
<button type="submit">Delete</button>
<input TYPE="hidden" name="remove" VALUE="<?php $resulting[WID]; ?>">
</form>

Answer 1

1. $the_WID = $_POST['WID'];应该是$the_WID = $_POST['remove'];.

2. 你需要回应你的价值: value="<?php echo $resulting[WID]; ?>"

3. 从这个问题的答案来看,似乎你不能.在占位符中使用:

BINDCHR = [:] [a-zA-Z0-9 _] +;

您可以使用字母数字+下划线.

将您的PHP更改为:

if(isset($_POST['remove'])){
    $the_WID = $_POST['remove'];
    echo "here is the WID" . $the_WID;

    $dlt = "DELETE FROM writing WHERE writing.WID = :writingWID";
    $stmtdlt = $dbh->prepare($dlt);
    $stmtdlt->bindParam(':writingWID', $the_WID, PDO::PARAM_INT);                                           
    $stmtdlt->execute(); 
}

和您的HTML表单:

<form action="" method="post">
<button type="submit">Delete</button>
<input type="hidden" name="remove" value="<?php echo $resulting[WID]; ?>">
</form>