bac*_*chr 44 java rest spring jpa spring-data
我正在尝试将自定义方法添加到我的Spring Data存储库PersonRepository,如1.3 Spring Data存储库的自定义实现中所述,并通过REST公开这些方法.初始代码来自使用REST示例访问JPA数据,以下是添加/修改类的代码:
interface PersonRepositoryCustom {
List<Person> findByFistName(String name);
}
class PersonRepositoryImpl implements PersonRepositoryCustom, InitializingBean {
@Override
public void afterPropertiesSet() throws Exception {
// initialization here
}
@Override
public List<Person> findByFistName(String name) {
// find the list of persons with the given firstname
}
}
@RepositoryRestResource(collectionResourceRel = "people", path = "people")
public interface PersonRepository extends PagingAndSortingRepository<Person, Long> {
List<Person> findByLastName(@Param("name") String name);
}
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当我运行应用程序并访问时http://localhost:8080/portfolio/search/,我得到以下响应正文:
{
"_links" : {
"findByLastName" : {
"href" : "http://localhost:8080/people/search/findByLastName{?name}",
"templated" : true
}
}
}
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findByFirstName即使在PersonRepository界面中可用,为什么不暴露?
此外,有没有办法动态/编程添加通过REST公开的存储库?
leo*_*leo 24
两天后,我已经用这种方式解决了.
自定义存储库接口:
public interface PersonRepositoryCustom {
Page<Person> customFind(String param1, String param2, Pageable pageable);
}
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自定义存储库实现
public class PersonRepositoryImpl implements PersonRepositoryCustom{
@Override
public Page<Person> customFind(String param1, String param2, Pageable pageable) {
// custom query by mongo template, entity manager...
}
}
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Spring Data Repository:
@RepositoryRestResource(collectionResourceRel = "person", path = "person")
public interface PersonRepository extends MongoRepository<Person, String>, PersonRepositoryCustom {
Page<Person> findByName(@Param("name") String name, Pageable pageable);
}
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Bean资源表示
public class PersonResource extends org.springframework.hateoas.Resource<Person>{
public PersonResource(Person content, Iterable<Link> links) {
super(content, links);
}
}
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资源汇编程序
@Component
public class PersonResourceAssembler extends ResourceAssemblerSupport<Person, PersonResource> {
@Autowired
RepositoryEntityLinks repositoryEntityLinks;
public PersonResourceAssembler() {
super(PersonCustomSearchController.class, PersonResource.class);
}
@Override
public PersonResource toResource(Person person) {
Link personLink = repositoryEntityLinks.linkToSingleResource(Person.class, person.getId());
Link selfLink = new Link(personLink.getHref(), Link.REL_SELF);
return new PersonResource(person, Arrays.asList(selfLink, personLink));
}
}
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自定义Spring MVC控制器
@BasePathAwareController
@RequestMapping("person/search")
public class PersonCustomSearchController implements ResourceProcessor<RepositorySearchesResource> {
@Autowired
PersonRepository personRepository;
@Autowired
PersonResourceAssembler personResourceAssembler;
@Autowired
private PagedResourcesAssembler<Person> pagedResourcesAssembler;
@RequestMapping(value="customFind", method=RequestMethod.GET)
public ResponseEntity<PagedResources> customFind(@RequestParam String param1, @RequestParam String param2, @PageableDefault Pageable pageable) {
Page personPage = personRepository.customFind(param1, param2, pageable);
PagedResources adminPagedResources = pagedResourcesAssembler.toResource(personPage, personResourceAssembler);
if (personPage.getContent()==null || personPage.getContent().isEmpty()){
EmbeddedWrappers wrappers = new EmbeddedWrappers(false);
EmbeddedWrapper wrapper = wrappers.emptyCollectionOf(Person.class);
List<EmbeddedWrapper> embedded = Collections.singletonList(wrapper);
adminPagedResources = new PagedResources(embedded, adminPagedResources.getMetadata(), adminPagedResources.getLinks());
}
return new ResponseEntity<PagedResources>(adminPagedResources, HttpStatus.OK);
}
@Override
public RepositorySearchesResource process(RepositorySearchesResource repositorySearchesResource) {
final String search = repositorySearchesResource.getId().getHref();
final Link customLink = new Link(search + "/customFind{?param1,param2,page,size,sort}").withRel("customFind");
repositorySearchesResource.add(customLink);
return repositorySearchesResource;
}
}
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Oli*_*ohm 22
这些方法没有暴露的原因是你基本上可以自由地在自定义存储库方法中实现任何你想要的东西,因此不可能推断出支持该特定资源的正确HTTP方法.
在你的情况下,使用普通GET可能没问题,在其他情况下,它可能必须是a,POST因为方法的执行有副作用.
目前的解决方案是制作一个自定义控制器来调用存储库方法.
小智 8
对于GET方法,我使用了以下方法:
@Query在Repository中创建一个虚方法(LogRepository.java)使用这种方法,我不必管理预测和资源组装.
@RepositoryRestResource(collectionResourceRel = "log", path = "log")
public interface LogRepository extends PagingAndSortingRepository<Log, Long>,
LogRepositoryCustom {
//NOTE: This query is just a dummy query
@Query("select l from Log l where l.id=-1")
Page<Log> findAllFilter(@Param("options") String options,
@Param("eid") Long[] entityIds,
@Param("class") String cls,
Pageable pageable);
}
public interface LogRepositoryCustom {
Page<Log> findAllFilter(@Param("options") String options,
@Param("eid") Long[] entityIds,
@Param("class") String cls,
Pageable pageable);
}
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在实现中,您可以自由使用存储库方法或直接转到持久层:
public class LogRepositoryImpl implements LogRepositoryCustom{
@Autowired
EntityManager entityManager;
@Autowired
LogRepository logRepository;
@Override
public Page<Log> findAllFilter(
@Param("options") String options,
@Param( "eid") Long[] entityIds,
@Param( "class" ) String cls,
Pageable pageable) {
//Transform kendoui json options to java object
DataSourceRequest dataSourceRequest=null;
try {
dataSourceRequest = new ObjectMapper().readValue(options, DataSourceRequest.class);
} catch (IOException ex) {
throw new RuntimeException(ex);
}
Session s = entityManager.unwrap(Session.class);
Junction junction = null;
if (entityIds != null || cls != null) {
junction = Restrictions.conjunction();
if (entityIds != null && entityIds.length > 0) {
junction.add(Restrictions.in("entityId", entityIds));
}
if (cls != null) {
junction.add(Restrictions.eq("cls", cls));
}
}
return dataSourceRequest.toDataSourceResult(s, Log.class, junction);
}
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