'handle_call'超时了

Question

我从GenServer中的句柄信息功能调用elixir genserver来添加电话号码获取表单客户端.但是一旦调用handle_call,所有者进程就会崩溃[timeout].请帮忙.

全局创建一个ETS以在调用任何下面描述的函数之前插入值.

def handle_info(message, state) do

    {a,b} = message
    phonenumber = b[:body] 
    add phonenumber
    {:noreply, state}
end

def add(phonenumber) do
    GenServer.call(__MODULE__, {:add, phonenumber})
end


def handle_call({:add, phonenumber}, from, state) do

    :ets.insert(:access_table, {:details, phonenumber})
    reply = {:ok, "Added #{phonenumber} to profile"}
    new_state = [{username} | state]
    {:reply, reply , new_state}
end

错误:

** When Server state == []
** Reason for termination == 
** {timeout,{gen_server,call,['Elixir.Bankrecord',{add,"346534543534"},5000]}}
** (EXIT from #PID<0.150.0>) exited in: :gen_server.call(Bankrecord, {:add, '346534543534'}, 5000)
** (EXIT) time out

Answer 1

您不能在调用中调用自己,就像在handle_info调用中调用addgen_server执行回调一样.由于所有操作都在gen_server中按顺序发生,因此您最终会阻止自己.该解决方案应该是使用一个简单的私人add模块的功能,并同时拥有handle_info并handle_call({:add委托给它.

def add(phonenumber) do
  GenServer.call(__MODULE__, {:add, phonenumber})
end

def handle_info({_, message}, state) do
  add_number message[:body]
  {:noreply, state}
end


def handle_call({:add, phonenumber}, from, state) do
  add_number phonenumber
  {:reply, {:ok, "Added #{phonenumber} to profile"} , [{username} | state]}
end

defp add_number(phonenumber) do
  :ets.insert(:access_table, {:details, phonenumber})
end