Mad*_*ess 4 php parse-platform
我正在尝试使用新的PHP SDK查询Parse.com.我安装了所有必要的东西.我在查询时遇到了问题.
链接:[ https://www.parse.com/docs/php_guide#queries]
我试过用这个:
require 'vendor/autoload.php';
use Parse\ParseClient;
use Parse\ParseObject;
ParseClient::initialize('secret1','secret2', 'secret3');
$query = new ParseQuery("TableName");
$query->equalTo("email", "email@me.com");
$results = $query->find();
echo "Successfully retrieved " . count($results) . " scores.");
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任何帮助将不胜感激!谢谢!!!!
使用William George的帮助解决了!这是我更新的代码:
require 'vendor/autoload.php';
use Parse\ParseClient;
use Parse\ParseObject;
use Parse\ParseQuery;
ParseClient::initialize('secret1','secret2', 'secret3');
try{
$query = new ParseQuery("TableName");
$query->equalTo("email", "email@me.com");
$results = $query->find();
echo "Successfully retrieved " . count($results) . " scores.";
} catch (Exception $e){
echo $e->getMessage();
}
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首先你有一个语法错误:
echo "Successfully retrieved " . count($results) . " scores.");
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应该
echo "Successfully retrieved " . count($results) . " scores.";
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其次你不包括 ParseQuery
use Parse\ParseQuery;
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此外,新的PHP Parse框架会在所有地方抛出异常.
将代码包装在try catch中.
try {
//parse code
} catch (\Exception $e){
echo $e->getMessage();
}
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输出现在说什么?