eha*_*ro2 3 sqlite pointers ios swift
我们正在使用Swift在iOS中实现SQLite,而不使用包装器或Objective-C桥接.一切正常,除了在进行查询和提取结果时.问题是UnsafePointer<UInt8>从Swite中的SQLite返回的,如下所示:
var querySQL = "SELECT address, phone FROM CONTACTS WHERE NAME = 'myName'"
var cQuery = querySQL.cStringUsingEncoding(NSUTF8StringEncoding)
var statement: COpaquePointer = nil
if sqlite3_prepare_v2(contactsDB, cQuery!, -1, &statement, nil) == SQLITE_OK {
if sqlite3_step(statement) == SQLITE_ROW {
var address : UnsafePointer<UInt8> = sqlite3_column_text(statement, 0)
var data = NSData(bytes: address, length: 10)
var string = NSString(data: data, encoding: NSUTF8StringEncoding)
println(string)
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如您所见,如果我们知道对象的长度(在本例中为10),我们可以将指针转换为String
为了深入研究这个问题,我有以下例子
let pointerFromString: UnsafePointer<Int8> = "xyz".cStringUsingEncoding(NSUTF8StringEncoding)
let stringFromPointer = String.fromCString(anotherPointerFromString_Int8) println(stringFromPointer!)
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鉴于这CChar是别名Int8,我可以将a转换String为UnsafePointer<Int8>使用.cStringUsingEncoding(),然后返回String使用.fromCString(<UnsafePointer_CChar>)
问题是我的SQLite结果是a UnsafePointer_UInt8,无法使用.fromCString()
底线问题是:是否可以转换或转换UnsafePointer_UInt8为UnsafePointer_Int8
Mar*_*n R 17
这应该工作:
let address = sqlite3_column_text(statement, 0)
let string = String.fromCString(UnsafePointer<CChar>(address))
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更新Swift 3(Xcode 8),比较Swift 3:将以null结尾的UnsafePointer <UInt8>转换为字符串:
let string = String(cString: sqlite3_column_text(statement, 0))
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