Kev*_*vin 22 laravel eloquent laravel-4
我目前正在尝试创建嵌套查询,如下所示:
public function getChallenge($user_id, $opponent_id)
{
$challenge = $this->challenges()
->where('open', true)
->where(function($query) use ($user_id, $opponent_id) {
$query->where('player_1', $user_id)
->where('player_2', $opponent_id);
})
->orWhere(function($query) use ($opponent_id, $user_id) {
$query->where('player_1', $opponent_id)
->where('player_2', $user_id);
})
->first();
return $challenge;
}
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这会创建以下查询,例如:
select * from `site_challenges_leagues`
where `site_challenges_leagues`.`league_id` = '1'
and `open` = '1'
and (`player_1` = '3' and `player_2` = '1')
or (`player_1` = '1' and `player_2` = '3')
limit 1
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但是,这总是返回表中的第一个值(其中open是1或者0),这是不正确的.为了使查询正确,它需要AND在括号中包含两组查询,如下所示:
select * from `site_challenges_leagues`
where `site_challenges_leagues`.`league_id` = '1'
and `open` = TRUE
and ((`player_1` = '3' and `player_2` = '1')
or (`player_1` = '1' and `player_2` = '3'))
limit 1
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在Laravel可以这样做吗?我试图这样做; 然而,它失败了:
public function getChallenge($user_id, $opponent_id)
{
$challenge = $this->challenges()
->where('open', true)
->where(function($q) use ($user_id, $opponent_id) {
$q->where(function($query) {
$query->where('player_1', $user_id)
->where('player_2', $opponent_id);
})
->orWhere(function($query) {
$query->where('player_1', $opponent_id)
->where('player_2', $user_id);
})
})
->first();
return $challenge;
}
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任何帮助是极大的赞赏.
Raz*_*zor 34
你非常接近答案
$challenge = $this->challenges()
->where('open', true)
->where(function($q) use ($user_id, $opponent_id) {
$q->where(function($query) use ($opponent_id, $user_id){
$query->where('player_1', $user_id)
->where('player_2', $opponent_id);
})
->orWhere(function($query) use ($opponent_id, $user_id) {
$query->where('player_1', $opponent_id)
->where('player_2', $user_id);
});
})
->first();
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以下是两个代码之间的差异
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