Rub*_*ben 9 php ajax request yii2
当我使用此代码时,我将此错误作为响应:
错误请求(#400):无法验证您的数据
/**
* Active toggle
*/
$(document).on('click', '[data-toggle-active-menu-items]', function(e){
e.preventDefault();
var id = $(this).data('toggle-active-menu-items');
$.ajax({
url: 'active',
type: 'POST',
data: {'id': id, _csrf: yii.getCsrfToken()},
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function(data) {
if (data.active == 1)
{
$('#list-' + id + ' [data-toggle-active-menu-items]').html('<span class="glyphicon glyphicon-eye-open"></span>');
} else {
$('#list-' + id + ' [data-toggle-active-menu-items]').html('<span class="glyphicon glyphicon-eye-close"></span>');
}
}
});
});
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我尝试添加
_csrf:yii.getCsrfToken()
和
contentType:"application/json; charset = utf-8",
dataType:"json",
但那不起作用
当我将它添加到我的控制器时,它确实有效,但这不好,我不想禁用csrf验证
public $ enableCsrfValidation = false;
我怎样才能解决这个问题?
小智 13
你可以试试这种方式.这是工作!
var csrfToken = $('meta[name="csrf-token"]').attr("content");
$.ajax({
url: 'request',
type: 'post',
dataType: 'json',
data: {param1: param1, _csrf : csrfToken},
});
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$.ajax({
url: '$urlSave',
type: 'post',
data: {payload: payload, _csrf: yii.getCsrfToken()},
dataType: 'json',
}).success(function(response) {
});
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其他例子:http://docs.mirocow.com/doku.php?id = yii2:docs#добавление_csrftoken_в_ajax_запрос_yii2
将此代码添加到布局的底部:
<script>
$.ajaxSetup({
data: <?= \yii\helpers\Json::encode([
\yii::$app->request->csrfParam => \yii::$app->request->csrfToken,
]) ?>
});
</script>
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这是我现在的代码,只需忽略 csrf 令牌:
$(document).on('click', '[data-toggle-active-menu-items]', function(e){
e.preventDefault();
var id = $(this).data('toggle-active-menu-items');
$.ajax({
url: 'active',
type: 'POST',
data: {'id': id},
dataType: "json",
success: function(data) {
if (data.active == 1)
{
$('#list-' + id + ' [data-toggle-active-menu-items]').html('<span class="glyphicon glyphicon-eye-open"></span>');
} else {
$('#list-' + id + ' [data-toggle-active-menu-items]').html('<span class="glyphicon glyphicon-eye-close"></span>');
}
}
});
});
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