我有以下10000000x2矩阵:
0 0
1 1
2 2
.. ..
10000000 10000000
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现在我想将这个矩阵保存到int[][]数组:
import com.google.common.base.Stopwatch;
static void memory(int size) throws Exception {
System.out.println("Memory");
Stopwatch s = Stopwatch.createStarted();
int[][] l = new int[size][2];
for (int i = 0; i < size; i++) {
l[i][0] = i;
l[i][1] = i;
}
System.out.println("Keeping " + size + " rows in-memory: " + s.stop());
}
public static void main(String[] args) throws Exception {
int size = 10000000;
memory(size);
memory(size);
memory(size);
memory(size);
memory(size);
}
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输出:
Keeping 10000000 rows in-memory: 2,945 s
Keeping 10000000 rows in-memory: 408,1 ms
Keeping 10000000 rows in-memory: 761,5 ms
Keeping 10000000 rows in-memory: 543,7 ms
Keeping 10000000 rows in-memory: 408,2 ms
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现在我想将此矩阵保存到磁盘:
import com.google.common.base.Stopwatch;
import java.io.BufferedOutputStream;
import java.io.FileOutputStream;
static void file(int size, int fileIndex) throws Exception {
Stopwatch s = Stopwatch.createStarted();
FileOutputStream outputStream = new FileOutputStream("D:\\file" + fileIndex);
BufferedOutputStream buf = new BufferedOutputStream(outputStream);
for (int i = 0; i < size; i++) {
buf.write(bytes(i));
buf.write(bytes(i));
}
buf.close();
outputStream.close();
System.out.println("Writing " + size + " rows: " + s.stop());
}
public static void main(String[] args) throws Exception {
int size = 10000000;
file(size, 1);
file(size, 2);
file(size, 3);
file(size, 4);
file(size, 5);
}
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输出:
Writing 10000000 rows: 715,8 ms
Writing 10000000 rows: 636,6 ms
Writing 10000000 rows: 614,6 ms
Writing 10000000 rows: 598,0 ms
Writing 10000000 rows: 611,9 ms
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不应该更快地保存到内存?
jwe*_*ing 21
正如评论中所说,你没有衡量任何有用的东西.JVM将写操作缓存在其内存中,然后将其刷新到操作系统,操作系统将其缓存在其内存中,然后在某个时刻将其写入磁盘.
但是,您只是在测量JVM将其缓存在自己的内存中所花费的时间(这是您可以测量的全部内容).
无论如何,你不应该为这种微观优化而烦恼.
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