symfony2:检查isGranted是否有路由

Question

假设某些路由字符串如"/path/index.html"受防火墙保护,如何判断当前用户是否能够访问它？

提前致谢!

对不起,我应该更明确一点:我有一系列路由名称,我构建了一个菜单.许多具有不同角色的用户可以使用此菜单访问页面.目的是在此菜单中仅显示特定用户的可访问权限.

就像是:

'security_context'->'user'->isGranted('/path/index.html')

Answer 1

这个答案基于您的评论:您应该获得访问该路由所需的角色.您需要访问security.access_map私有服务.因此必须直接注入.eg :您可以创建一个path_roles类似于您的服务可以获得某个路径的角色:

namespace Acme\FooBundle;

class PathRoles
{
    protected $accessMap;

    public function __construct($accessMap)
    {
        $this->accessMap = $accessMap;
    }

    public function getRoles($path)
    { //$path is the path you want to check access to

        //build a request based on path to check access
        $request = Symfony\Component\HttpFoundation\Request::create($path, 'GET');
        list($roles, $channel) = $this->accessMap->getPatterns($request);//get access_control for this request

        return $roles;
    }
}

现在将其声明为服务:

services:
    path_roles:
        class: 'Acme\FooBundle\PathRoles'
        arguments: ['@security.access_map']

现在在控制器中使用该服务来获取路径的角色并根据这些角色和isGranted.ie构建菜单:

  //code from controller
  public function showAction(){
      //do stuff and get the link path for the menu,store it in $paths
      $finalPaths=array();
      foreach($paths as $path){
      $roles = $this->get('path_roles')->getRoles($path);
      foreach($roles as $role){
          $role = $role->getRole();//not sure if this is needed
          if($this->get('security.context')->isGranted($role)){
              $finalPaths[] = $path;
              break;
          }
      }
     //now construct your menu based on $finalPaths
      }
  }