删除仅在列表开头出现的0

Question

我有一个列表,在我想要删除的开头有0.0确实发生在数据的其他地方,但我想保留这些.

l=[0, 0, 0, 0, 151, 199, 149, 147, 281, 133, 166, 162, 0, 353, 867, 1060, 525, 1031, 420, 0, 832, 1114, 869, 531, 546, 555, 520, 679, 715, 669, 555, 888, 605, 809, 0, 514]

需要成为:

l=[151, 199, 149, 147, 281, 133, 166, 162, 0, 353, 867, 1060, 525, 1031, 420, 0, 832, 1114, 869, 531, 546, 555, 520, 679, 715, 669, 555, 888, 605, 809, 0, 514]

Answer 1

使用itertools.dropwhile()砸大笔钱:

from itertools import dropwhile
import operator

l = list(dropwhile(operator.not_, l))

这将只丢弃初始的0值; 或者更确切地说,所有的假y值,使用operator.not_().

演示:

>>> from itertools import dropwhile
>>> import operator
>>> l=[0, 0, 0, 0, 151, 199, 149, 147, 281, 133, 166, 162, 0, 353, 867, 1060, 525, 1031, 420, 0, 832, 1114, 869, 531, 546, 555, 520, 679, 715, 669, 555, 888, 605, 809, 0, 514]
>>> list(dropwhile(operator.not_, l))
[151, 199, 149, 147, 281, 133, 166, 162, 0, 353, 867, 1060, 525, 1031, 420, 0, 832, 1114, 869, 531, 546, 555, 520, 679, 715, 669, 555, 888, 605, 809, 0, 514]