我已经通过新的simple_form functionnality实现了自定义身份验证器
main:
pattern: ^/
simple_form:
authenticator: custom_authenticator
provider: fos_userbundle
csrf_provider: form.csrf_provider
remember_me:
key: "%secret%"
lifetime: 31536000 # 365 jours
path: /
domain: ~
name: my_remember_cookie
Run Code Online (Sandbox Code Playgroud)
我的Authenticator中的authenticateToken()方法如下所示:
try {
$user = $userProvider->loadUserByUsername($token->getUsername());
} catch (UsernameNotFoundException $e) {
throw new AuthenticationException('Unknown user');
}
if ($user->isLocked() === true) {
throw new AuthenticationException('User locked');
}
if (/* Logic checks */) {
return new UsernamePasswordToken(
$user, null, $providerKey, $user->getRoles()
);
}
Run Code Online (Sandbox Code Playgroud)
我想知道,从这一点来说,是否有一种方法以编程方式设置记住我的cookie(在我的情况下,我想根据用户的角色设置它)?
编辑:我解决了它感谢sebbo,重点是在将请求对象传递给rememberMe服务之前手动设置$ request对象中的remember_me参数.
我的最终代码:
/**
* onAuthenticationSuccess
*
* @param Request $request
* @param TokenInterface $token
* @return Response
*/
public function onAuthenticationSuccess(Request $request, TokenInterface $token) {
$url = $this->container->get("session")->get('_security.main.target_path') ? $this->container->get("session")->get('_security.main.target_path') : $this->container->get("router")->generate('home');
$response = $request->isXmlHttpRequest() ?
new JsonResponse(array(
"success" => true,
"url" => $url
)) : new RedirectResponse($url);
// Relevant part
$rememberMeService = $this->container->get("EDE.security.service.remember_me");
$request->attributes->set($rememberMeService->getRememberMeParameter(), 'true'/*set to other than 'yes'|'true'|'on'|'1' to force to don't set cookie*/);
$rememberMeService->loginSuccess($request, $response, $token);
return $response;
}
Run Code Online (Sandbox Code Playgroud)
服务别名:
<service id="EDE.security.service.remember_me" alias="security.authentication.rememberme.services.simplehash.main"></service>
Run Code Online (Sandbox Code Playgroud)
手动请求参数分配似乎有点脏,但它的工作原理.
要以编程方式设置记住我的cookie,我们在应用程序中使用以下代码:
// setting the remember me token
$this->container->get('our_company.security.service.remember_me')->loginSuccess(
$request,
$response,
$this->container->get('security.context')->getToken()
);
Run Code Online (Sandbox Code Playgroud)
请考虑服务定义our_company.security.service.remember_me仅是Symfony2记住我服务的别名.我们必须创建这个别名,以便让我记住我的服务.
这是服务定义:
<service id="our_company.security.service.remember_me" alias="security.authentication.rememberme.services.simplehash.main"/>
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
1516 次 |
| 最近记录: |