java中的html截断器

Question

是否有任何实用程序(或示例源代码)在Java中截断HTML(用于预览)？我想在服务器上而不是在客户端上进行截断.

我正在使用HTMLUnit来解析HTML.

更新:
我希望能够预览HTML,因此截断器将保持HTML结构,同时在所需的输出长度后删除元素.

Answer 1

我编写了另一个 java 版本的 truncateHTML。此函数将字符串截断至多个字符，同时保留整个单词和 HTML 标签。

public static String truncateHTML(String text, int length, String suffix) {
    // if the plain text is shorter than the maximum length, return the whole text
    if (text.replaceAll("<.*?>", "").length() <= length) {
        return text;
    }
    String result = "";
    boolean trimmed = false;
    if (suffix == null) {
        suffix = "...";
    }

    /*
     * This pattern creates tokens, where each line starts with the tag.
     * For example, "One, <b>Two</b>, Three" produces the following:
     *     One,
     *     <b>Two
     *     </b>, Three
     */
    Pattern tagPattern = Pattern.compile("(<.+?>)?([^<>]*)");

    /*
     * Checks for an empty tag, for example img, br, etc.
     */
    Pattern emptyTagPattern = Pattern.compile("^<\\s*(img|br|input|hr|area|base|basefont|col|frame|isindex|link|meta|param).*>$");

    /*
     * Modified the pattern to also include H1-H6 tags
     * Checks for closing tags, allowing leading and ending space inside the brackets
     */
    Pattern closingTagPattern = Pattern.compile("^<\\s*/\\s*([a-zA-Z]+[1-6]?)\\s*>$");

    /*
     * Modified the pattern to also include H1-H6 tags
     * Checks for opening tags, allowing leading and ending space inside the brackets
     */
    Pattern openingTagPattern = Pattern.compile("^<\\s*([a-zA-Z]+[1-6]?).*?>$");

    /*
     * Find &nbsp; &gt; ...
     */
    Pattern entityPattern = Pattern.compile("(&[0-9a-z]{2,8};|&#[0-9]{1,7};|[0-9a-f]{1,6};)");

    // splits all html-tags to scanable lines
    Matcher tagMatcher =  tagPattern.matcher(text);
    int numTags = tagMatcher.groupCount();

    int totalLength = suffix.length();
    List<String> openTags = new ArrayList<String>();

    boolean proposingChop = false;
    while (tagMatcher.find()) {
        String tagText = tagMatcher.group(1);
        String plainText = tagMatcher.group(2);

        if (proposingChop &&
                tagText != null && tagText.length() != 0 &&
                plainText != null && plainText.length() != 0) {
            trimmed = true;
            break;
        }

        // if there is any html-tag in this line, handle it and add it (uncounted) to the output
        if (tagText != null && tagText.length() > 0) {
            boolean foundMatch = false;

            // if it's an "empty element" with or without xhtml-conform closing slash
            Matcher matcher = emptyTagPattern.matcher(tagText);
            if (matcher.find()) {
                foundMatch = true;
                // do nothing
            }

            // closing tag?
            if (!foundMatch) {
                matcher = closingTagPattern.matcher(tagText);
                if (matcher.find()) {
                    foundMatch = true;
                    // delete tag from openTags list
                    String tagName = matcher.group(1);
                    openTags.remove(tagName.toLowerCase());
                }
            }

            // opening tag?
            if (!foundMatch) {
                matcher = openingTagPattern.matcher(tagText);
                if (matcher.find()) {
                    // add tag to the beginning of openTags list
                    String tagName = matcher.group(1);
                    openTags.add(0, tagName.toLowerCase());
                }
            }

            // add html-tag to result
            result += tagText;
        }

        // calculate the length of the plain text part of the line; handle entities (e.g. &nbsp;) as one character
        int contentLength = plainText.replaceAll("&[0-9a-z]{2,8};|&#[0-9]{1,7};|[0-9a-f]{1,6};", " ").length();
        if (totalLength + contentLength > length) {
            // the number of characters which are left
            int numCharsRemaining = length - totalLength;
            int entitiesLength = 0;
            Matcher entityMatcher = entityPattern.matcher(plainText);
            while (entityMatcher.find()) {
                String entity = entityMatcher.group(1);
                if (numCharsRemaining > 0) {
                    numCharsRemaining--;
                    entitiesLength += entity.length();
                } else {
                    // no more characters left
                    break;
                }
            }

            // keep us from chopping words in half
            int proposedChopPosition = numCharsRemaining + entitiesLength;
            int endOfWordPosition = plainText.indexOf(" ", proposedChopPosition-1);
            if (endOfWordPosition == -1) {
                endOfWordPosition = plainText.length();
            }
            int endOfWordOffset = endOfWordPosition - proposedChopPosition;
            if (endOfWordOffset > 6) { // chop the word if it's extra long
                endOfWordOffset = 0;
            }

            proposedChopPosition = numCharsRemaining + entitiesLength + endOfWordOffset;
            if (plainText.length() >= proposedChopPosition) {
                result += plainText.substring(0, proposedChopPosition);
                proposingChop = true;
                if (proposedChopPosition < plainText.length()) {
                    trimmed = true;
                    break; // maximum length is reached, so get off the loop
                }
            } else {
                result += plainText;
            }
        } else {
            result += plainText;
            totalLength += contentLength;
        }
        // if the maximum length is reached, get off the loop
        if(totalLength >= length) {
            trimmed = true;
            break;
        }
    }

    for (String openTag : openTags) {
        result += "</" + openTag + ">";
    }
    if (trimmed) {
        result += suffix;
    }
    return result;
}

Answer 2

我认为您需要编写自己的 XML 解析器来完成此任务。拉出主体节点，添加节点直到二进制长度<某个固定大小，然后重建文档。如果 HTMLUnit 不创建语义 XHTML，我建议使用tagoup。

如果您需要 XML 解析器/处理程序，我推荐XOM。