-1 java if-statement button void jtextfield
我正在尝试做一个程序,如果两个TextFields等于某个值会发生什么,我有两个if语句.当第一个if语句发生时,第二个if语句发生但我在代码中设置的值不匹配.为了更好地解释,这里是代码:
private void LevelUp(){
float level = (float) Double.parseDouble(lvl.getText());
float expmn = (float) Double.parseDouble(ExpMin.getText());
if(level == 1 && expmn == 500){
lvl.setText("2");
ExpMin.setText("501");
ExpMax.setText("1000");
JOptionPane.showMessageDialog(null,"" + "levevlup!" ,"Para Yok",JOptionPane.PLAIN_MESSAGE);
if(level == 2 && expmn == 1000);
lvl.setText("3");
ExpMin.setText("1001");
ExpMax.setText("2500");
}
else{
JOptionPane.showMessageDialog(null,"" + "leveladssadaup" ,"Para Yok",JOptionPane.PLAIN_MESSAGE);
}
}
}
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你不仅应该;在if-statement之后删除你在哪里寻找level2,但是如果我正确地查看你的代码,你应该关闭你的if语句,在你要求level2之前你找到level1,如果是level2则使用else.
如果出现以下情况,请在level2之后选择大括号:
if(level == 1 && expmn == 500){
lvl.setText("2");
ExpMin.setText("501");
ExpMax.setText("1000");
JOptionPane.showMessageDialog(null,"" + "levevlup!" ,"Para Yok",JOptionPane.PLAIN_MESSAGE);
}// <-- close level1 here because you want to check for a new level afterwards
else if(level == 2 && expmn == 1000){ //<-- here was your ;, which was wrong
lvl.setText("3");
ExpMin.setText("1001");
ExpMax.setText("2500");
}
else{
JOptionPane.showMessageDialog(null,"" + "leveladssadaup" ,"Para Yok",JOptionPane.PLAIN_MESSAGE);
}
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