如何匹配具有多个字段的选项？

Question

如何匹配具有多个字段的选项？我有以下代码:

let opt_windowrecv = glfw_context.create_window(1280, 720, "Hello World!", glfw::Windowed); // returns Option<(Window, Receiver<(f64, WindowEvent)>)>

let window = match opt_windowrecv { // Does not compile
    Some(window, _) => window,
    None            => return
};

它抱怨说:

此模式有2个字段,但相应的变量有1个字段

但是,使用此解决方法确实有效:

let opt_windowrecv = glfw_context.create_window(1280, 720, "Hello World!", glfw::Windowed); // returns Option<(Window, Receiver<(f64, WindowEvent)>)>

let windowrecv = match opt_windowrecv {
    Some(windowrecv) => windowrecv,
    None            => return
};

let (window, _) = windowrecv;

我做错了什么,或者这是Rust编译器中的错误？我正在使用glfw-rs库.

Answer 1

let window = match opt_windowrecv {
    Some((window, _)) => window,
    None            => return
};

应该管用.解构Some应该是一个元组,而不是两个参数.