mak*_*ake 10 c visual-studio-2008 visual-studio visual-c++ gettimeofday
有人可以帮我在Windows XP上使用Visual Studio C++ 2008的gettimeofday()函数吗?这是我在网上找到的代码:
#include < time.h >
#include <windows.h>
#if defined(_MSC_VER) || defined(_MSC_EXTENSIONS)
#define DELTA_EPOCH_IN_MICROSECS 11644473600000000Ui64
#else
#define DELTA_EPOCH_IN_MICROSECS 11644473600000000ULL
#endif
struct timezone
{
int tz_minuteswest; /* minutes W of Greenwich */
int tz_dsttime; /* type of dst correction */
};
int gettimeofday(struct timeval *tv, struct timezone *tz)
{
FILETIME ft;
unsigned __int64 tmpres = 0;
static int tzflag;
if (NULL != tv)
{
GetSystemTimeAsFileTime(&ft);
tmpres |= ft.dwHighDateTime;
tmpres <<= 32;
tmpres |= ft.dwLowDateTime;
/*converting file time to unix epoch*/
tmpres -= DELTA_EPOCH_IN_MICROSECS;
tmpres /= 10; /*convert into microseconds*/
tv->tv_sec = (long)(tmpres / 1000000UL);
tv->tv_usec = (long)(tmpres % 1000000UL);
}
if (NULL != tz)
{
if (!tzflag)
{
_tzset();
tzflag++;
}
tz->tz_minuteswest = _timezone / 60;
tz->tz_dsttime = _daylight;
}
return 0;
}
...
// call gettimeofday()
gettimeofday(&tv, &tz);
tm = localtime(&tv.tv_sec);
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去年,当我使用VC++ 6测试此代码时,它工作正常.但是现在当我使用VC++ 2008时,我收到异常处理错误.那么有没有关于如何使用gettimeofday或类似东西的想法?
感谢您的回复,我们非常感谢您的帮助:
Neo*_*der 20
在UNIX中,时区结构的使用已过时.我不知道你为什么要用它.请参阅http://linux.about.com/od/commands/l/blcmdl2_gettime.htm但是如果您想使用此结构来了解当地时间的GMT(UTC)差异,那将是下一个:tz_minuteswest是真正的差异从GMT(UTC)开始的分钟数和tz_dsttime是一个标志,表示日光是否正在使用中.
您的示例有一些更改在Visual C++ 2008 Express中正常工作:
#include "stdafx.h"
#include <time.h>
#include <windows.h>
const __int64 DELTA_EPOCH_IN_MICROSECS= 11644473600000000;
/* IN UNIX the use of the timezone struct is obsolete;
I don't know why you use it. See http://linux.about.com/od/commands/l/blcmdl2_gettime.htm
But if you want to use this structure to know about GMT(UTC) diffrence from your local time
it will be next: tz_minuteswest is the real diffrence in minutes from GMT(UTC) and a tz_dsttime is a flag
indicates whether daylight is now in use
*/
struct timezone2
{
__int32 tz_minuteswest; /* minutes W of Greenwich */
bool tz_dsttime; /* type of dst correction */
};
struct timeval2 {
__int32 tv_sec; /* seconds */
__int32 tv_usec; /* microseconds */
};
int gettimeofday(struct timeval2 *tv/*in*/, struct timezone2 *tz/*in*/)
{
FILETIME ft;
__int64 tmpres = 0;
TIME_ZONE_INFORMATION tz_winapi;
int rez=0;
ZeroMemory(&ft,sizeof(ft));
ZeroMemory(&tz_winapi,sizeof(tz_winapi));
GetSystemTimeAsFileTime(&ft);
tmpres = ft.dwHighDateTime;
tmpres <<= 32;
tmpres |= ft.dwLowDateTime;
/*converting file time to unix epoch*/
tmpres /= 10; /*convert into microseconds*/
tmpres -= DELTA_EPOCH_IN_MICROSECS;
tv->tv_sec = (__int32)(tmpres*0.000001);
tv->tv_usec =(tmpres%1000000);
//_tzset(),don't work properly, so we use GetTimeZoneInformation
rez=GetTimeZoneInformation(&tz_winapi);
tz->tz_dsttime=(rez==2)?true:false;
tz->tz_minuteswest = tz_winapi.Bias + ((rez==2)?tz_winapi.DaylightBias:0);
return 0;
}
int _tmain(int argc, _TCHAR* argv[])
{
struct timeval2 tv;
struct timezone2 tz;
struct tm *tm1;
time_t time1;
ZeroMemory(&tv,sizeof(tv));
ZeroMemory(&tz,sizeof(tz));
gettimeofday(&tv, &tz); // call gettimeofday()
time1=tv.tv_sec;
tm1 = localtime(&time1);
FILE *f;
f=fopen("rez.txt","w");
fprintf(f,"%04d.%02d.%02d %02d:%02d:%02d\n",1900+tm1->tm_year,1+tm1->tm_mon,tm1->tm_mday,tm1->tm_hour,tm1->tm_min,tm1->tm_sec);
fprintf(f,"Diffrence between GMT(UTC) and local time=%d %s\n",tz.tz_minuteswest,"minutes");
fprintf(f,"Is Daylight now=%s\n",tz.tz_dsttime?"Yes":"No");
fclose(f);
return 0;
}
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秒表简单秒表
FWIW:这与 Kate 的相似,但我只想提一下,如果有人在 C++ 中寻找最简单的秒表(计数秒)。没什么大不了的,我知道。它只有 1 秒的分辨率,因此如果您想计算微秒,请继续其他示例。
double seconds=0;
time_t timer1, timer2;
time(&timer1); /* get current time */
...
time(&timer2); /* get current time later */
seconds = difftime(timer2,timer1);
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有几种不同的类型来表示时间。这是我最近使用的一些代码:
time_t now;
time(&now);
tm* local = localtime(&now);
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然后我继续用 的片段构建一个字符串local
,但此时你可以做你想做的事情。
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