我有一个带点分隔字符列的数据框:
> set.seed(310366)
> tst = data.frame(x=1:10,y=paste(sample(c("FOO","BAR","BAZ"),10,TRUE),".",sample(c("foo","bar","baz"),10,TRUE),sep=""))
> tst
x y
1 1 BAR.baz
2 2 FOO.foo
3 3 BAZ.baz
4 4 BAZ.foo
5 5 BAZ.bar
6 6 FOO.baz
7 7 BAR.bar
8 8 BAZ.baz
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我想将该列拆分为两个新列,其中包含点两侧的部分.str_split_fixed从包中stringr可以很好地完成这项工作.我的所有值肯定是用点分隔的两个部分,所以我可以这样做:
> require(stringr)
> str_split_fixed(tst$y,"\\.",2)
[,1] [,2]
[1,] "BAR" "baz"
[2,] "FOO" "foo"
[3,] "BAZ" "baz"
[4,] "BAZ" "foo"
[5,] "BAZ" "bar"
[6,] "FOO" "baz"
[7,] "BAR" "bar"
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现在我可以把cbind它放到我的数据框架上,但我想我会弄清楚如何在dplyr管道中做到这一点.首先,我认为mutate可以做到一个:
> tst %.% mutate(parts=str_split_fixed(y,"\\.",2))
Error: wrong result size (20), expected 10 or 1
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我可以mutate用两个来做:
> tst %.% mutate(part1=str_split_fixed(y,"\\.",2)[,1], part2=str_split_fixed(y,"\\.",2)[,2])
x y part1 part2
1 1 BAR.baz BAR baz
2 2 FOO.foo FOO foo
3 3 BAZ.baz BAZ baz
4 4 BAZ.foo BAZ foo
5 5 BAZ.bar BAZ bar
6 6 FOO.baz FOO baz
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但那是两次运行字符串.
"最好的"我在dplyr某种程度上可以做到这一点(我在写这个问题时才发现......):
> tst %.% do(cbind(.,data.frame(parts=str_split_fixed(.$y,"\\.",2))))
x y parts.1 parts.2
1 1 BAR.baz BAR baz
2 2 FOO.foo FOO foo
3 3 BAZ.baz BAZ baz
4 4 BAZ.foo BAZ foo
5 5 BAZ.bar BAZ bar
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这还不错,但在R中失去了管道事物的很多可读性.是否有一个简单的方法使用mutate我错过了?
bee*_*oot 37
您可以使用separate()从tidyr与组合dplyr:
tst %>% separate(y, c("y1", "y2"), sep = "\\.", remove=FALSE)
x y y1 y2
1 1 BAR.baz BAR baz
2 2 FOO.foo FOO foo
3 3 BAZ.baz BAZ baz
4 4 BAZ.foo BAZ foo
5 5 BAZ.bar BAZ bar
6 6 FOO.baz FOO baz
7 7 BAR.bar BAR bar
8 8 BAZ.baz BAZ baz
9 9 FOO.bar FOO bar
10 10 BAR.foo BAR foo
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设置remove=TRUE将删除列y