use*_*686 3 angularjs angularjs-directive
我正在AngularJS指令中执行我的第一步.只需将此项设置为练习即可输出产品名称:
.directive('productname', function (Prefs) {
return {
restrict: 'E',
replace: true,
transclude: true,
templateUrl: '/partials/productname.html',
link: function (scope, element, attrs) {
scope.brand = Prefs.owner;
}
}
})
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productname.html
<span class="productname"><span class="brand">{{brand}}</span> <span class="product" ng-transclude>{{productname}}</span></span>
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这样用法很明显: <productname>{{product.name}}</productname>
现在,有人可以告诉我如何通过添加一个标志来输出链接的productname来使这个指令可配置吗?
用法是:<productname linked>{{product.name}}</productname>输出/模板将是:
<span class="productname"><a href="/edit/{{id}}"> <span class="brand">{{brand}}</span> <span class="product" ng-transclude>{{productname}}</span></a></span>
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看起来很复杂,我无法弄清楚逻辑应该注入的位置......
首先,您应该使用scope指令声明的属性.此外,transclude在这种情况下你不需要.像这样:
.directive('productname', function (Prefs) {
return {
restrict: 'E',
scope: {
product: "=",
linked: "="
},
replace: true,
templateUrl: '/partials/productname.html',
link: function (scope, element, attrs) {
// scope.product and scope.linked are automatically set
scope.brand = Prefs.owner;
}
}
})
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和模板:
<span class="productname" ng-switch="linked">
<a href="/edit/{{id}}" ng-switch-when="true">
<span class="brand">{{brand}}</span>
<span class="product">{{product.name}}</span>
</a>
<span ng-switch-default>
<span class="brand">{{brand}}</span>
<span class="product">{{product.name}}</span>
</span>
</span>
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像这样调用模板:
<productname product="product"></productname>
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要么:
<productname product="product" linked="'true'"></productname>
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如果要将该linked属性用作标志,可以使用attrs变量:
.directive('productname', function (Prefs) {
return {
restrict: 'E',
scope: {
product: "="
},
replace: true,
templateUrl: '/partials/productname.html',
link: function (scope, element, attrs) {
// scope.product is automatically set
scope.linked = typeof attrs.linked != 'undefined';
scope.brand = Prefs.owner;
}
}
})
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这样称呼它:
<productname product="product" linked></productname>
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