使用按钮更改变量的值(Tkinter)

Question

我想用一个按钮改变一个变量的值,我不想像这样创建一个新的整个函数:

from Tkinter import *
variable = 1
def makeSomething():
    global variable
    variable = 2
root = Tk()
myButton = Button(root, text='Press me',command=makeSomething).pack()

我怎么能这样做？(我需要为六个按钮做这个,制作六个功能不是一个选项)

Answer 1

我需要为6个按钮做这个...

如果每个按钮修改相同的全局变量,则makeSomething接受一个value参数:

from Tkinter import *
variable = 1
def makeSomething(value):
    global variable
    variable = value
root = Tk()
Button(root, text='Set value to four',command=lambda *args: makeSomething(4)).pack()
Button(root, text='Set value to eight',command=lambda *args: makeSomething(8)).pack()
Button(root, text='Set value to fifteen',command=lambda *args: makeSomething(15)).pack()
#...etc

如果每个按钮修改不同的全局,则将所有全局变量压缩为单个全局变量,然后makeSomething可以修改.

from Tkinter import *
settings = {"foo": 1, "bar": 1, "baz": 1}

def makeSomething(name):
    settings[name] = 2

root = Tk()
Button(root, text='Set foo',command=lambda *args: makeSomething("foo")).pack()
Button(root, text='Set bar',command=lambda *args: makeSomething("bar")).pack()
Button(root, text='Set baz',command=lambda *args: makeSomething("baz")).pack()
#...etc

在任何一种情况下,您仍然只需要一个功能.

顺便说一下,不要这样做:

myButton = Button(root).pack()

这会将结果分配pack()给myButton,因此myButton将None代替引用您的按钮.相反,做:

myButton = Button(root)
myButton.pack()