如何通过Python获取3D彩色表面？

Question

如何通过Matplotlib获得以下表面？

在matlab中很容易通过:

mesh(peaks)

似乎matplotlib mesh在matlab 中没有完全对应的东西.在Wireframe plots没有任何colormap选项

Answer 1

似乎有可能使用matplotlib,即使它有点像黑客:

from mpl_toolkits.mplot3d import axes3d
from mpl_toolkits.mplot3d import art3d
import matplotlib.pyplot as plt
import numpy as np
import matplotlib as mpl

fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
X, Y, Z = axes3d.get_test_data(0.05)
wire = ax.plot_wireframe(X, Y, Z, rstride=10, cstride=10)

# Retrive data from internal storage of plot_wireframe, then delete it
nx, ny, _  = np.shape(wire._segments3d)
wire_x = np.array(wire._segments3d)[:, :, 0].ravel()
wire_y = np.array(wire._segments3d)[:, :, 1].ravel()
wire_z = np.array(wire._segments3d)[:, :, 2].ravel()
wire.remove()

# create data for a LineCollection
wire_x1 = np.vstack([wire_x, np.roll(wire_x, 1)])
wire_y1 = np.vstack([wire_y, np.roll(wire_y, 1)])
wire_z1 = np.vstack([wire_z, np.roll(wire_z, 1)])
to_delete = np.arange(0, nx*ny, ny)
wire_x1 = np.delete(wire_x1, to_delete, axis=1)
wire_y1 = np.delete(wire_y1, to_delete, axis=1)
wire_z1 = np.delete(wire_z1, to_delete, axis=1)
scalars = np.delete(wire_z, to_delete)

segs = [list(zip(xl, yl, zl)) for xl, yl, zl in \
                 zip(wire_x1.T, wire_y1.T, wire_z1.T)]

# Plots the wireframe by a  a line3DCollection
my_wire = art3d.Line3DCollection(segs, cmap="hsv")
my_wire.set_array(scalars)
ax.add_collection(my_wire)

plt.colorbar(my_wire)
plt.show()

Answer 2

在回答另一个问题时,我发现您可以轻松地使用它plot_surface来生成颜色映射表面,然后交换面部和边缘颜色:

surf = ax.plot_surface(X, Y, Z, rstride=2, cstride=2, shade=False, cmap="jet", linewidth=1)
draw()
surf.set_edgecolors(surf.to_rgba(surf._A))
surf.set_facecolors("white")
show()

产生

该解决方案相对于另一个解决方案的缺点是边缘不具有平滑的每像素着色,而是每个都有一种颜色.