解释python模块itertools的组合功能

Question

我经常itertools在Python中使用模块,但如果我不知道它背后的逻辑,那就像是作弊.

这是我的代码,当订单不重要时,找到字符串的组合.

def combinations(iterable, r):
    # combinations('ABCD', 2) --> AB AC AD BC BD CD
    # combinations(range(4), 3) --> 012 013 023 123
    pool = tuple(iterable)
    n = len(pool)
    if r > n:
        return
    indices = list(range(r))
    yield tuple(pool[i] for i in indices)
    while True:
        for i in reversed(range(r)):
            if indices[i] != i + n - r:
                break
        else:
            return
        indices[i] += 1
        for j in range(i+1, r):
            indices[j] = indices[j-1] + 1
        yield tuple(pool[i] for i in indices)

有人可以解释基本想法吗？特别是在第14行

Answer 1

def combinations(iterable, r):
    # combinations('ABCD', 2) --> AB AC AD BC BD CD
    # combinations(range(4), 3) --> 012 013 023 123
    pool = tuple(iterable)
    # first you create a tuple of the original input which you can refer later with 
    # the corresponding indices
    n = len(pool)
    # get the length of the tuple
    if r > n:
        return
    # if the length of the desired permutation is higher than the length of the tuple 
    # it is not possible to create permutations so return without doing something

    indices = list(range(r))
    # create the first list of indices in normal order ( indices = [0,1,2,3,...,r])
    # up to the desired range r

    yield tuple(pool[i] for i in indices)
    # return the first permutation which is a tuple of the input with the original 
    # indices up to r tuple(tuple[0], tuple[1],....,tuple[r])

    while True:
        for i in reversed(range(r)):
            # i will go from r-1, r-2, r-3, ....,0

            if indices[i] != i + n - r:
                # if condition is true except for the case 
                # that at the position i in the tuple the last possible 
                # character appears then it is equal and proceed with the character 
                # before which means that this character is replaced by the next 
                # possible one

                # example: tuple='ABCDE' so n = 5, r=3 indices is [0,1,2] at start i=2
                # yield (A,B,C)
                # indices[i] is 2 and checks if 2 != 4 (2 +5-3) is true and break
                # increase indices[i]+1 and yield (A,B,D)
                # indices[i] is 3 and checks if 3 != 4 (2 +5-3) is true and break
                # increase indices[i]+1 and yield (A,B,E) 
                # indices[i] is 4 and checks if 4 != 4 (2 +5-3) is false so next loop 
                # iteration:  i = 1 indices[i] is 1 and checks if 4 != 3 (1 +5-3) 
                # is true and break .... and so on

                break
        else:
            # when the forloop completely finished then all possible character 
            # combinations are processed and the function ends
            return

        indices[i] += 1 # as written proceed with the next character which means the 
                        # index at i is increased
        for j in range(i+1, r): 
            indices[j] = indices[j-1] + 1 # all the following indexes are increased as 
                                          # well since we only want to at following 
                                          # characters and not at previous one or the
                                          # same which is index at indice[i]
        yield tuple(pool[i] for i in indices)
        # return the new tuple