如何在IOS中使用经度和经度通过CLlocationManager获取城市名称？

Question

我试图通过CLLocationManager使用纬度和经度获取地址,但它只返回州和国家名称,我也想要城市,我附加我的代码可以任何人告诉我,我怎么能改变我的代码以获得城市名称.Below是我的代码

- (void)locationManager:(CLLocationManager *)manager didUpdateLocations:(NSArray *)locations
{
    currentLocation = [locations objectAtIndex:0];
    CLGeocoder *geocoder1 = [[CLGeocoder alloc] init];

     NSLog(@"Detected Location : %f, %f", currentLocation.coordinate.latitude, currentLocation.coordinate.longitude);

    //CLLocation *newLocation = [[CLLocation alloc]initWithLatitude:26.9260 longitude:75.8235];

    CLLocation *newLocation = [[CLLocation alloc]initWithLatitude:currentLocation.coordinate.latitude longitude:currentLocation.coordinate.longitude];

    [geocoder1 reverseGeocodeLocation:newLocation
                   completionHandler:^(NSArray *placemarks, NSError *error) {

                       if (error) {
                           NSLog(@"Geocode failed with error: %@", error);
                           return;
                       }

                       if (placemarks && placemarks.count > 0)
                       {
                           CLPlacemark *placemark = placemarks[0];

                           NSDictionary *addressDictionary =
                           placemark.addressDictionary;

                           NSLog(@"%@ ", addressDictionary);
                           NSString *address = [addressDictionary
                                                objectForKey:(NSString *)kABPersonAddressStreetKey];
                           NSString *city = [addressDictionary
                                             objectForKey:(NSString *)kABPersonAddressCityKey];
                           NSString *state = [addressDictionary
                                              objectForKey:(NSString *)kABPersonAddressStateKey];
                           NSString *zip = [addressDictionary
                                            objectForKey:(NSString *)kABPersonAddressZIPKey];


                           NSLog(@"%@ %@ %@ %@", address,city, state, zip);
                       }

                   }];
}

Answer 1

试试这个 ..

-(NSString*)getAddressFromLatLong : (NSString *)latLng {
    //  NSString *string = [[Address.text stringByAppendingFormat:@"+%@",cityTxt.text] stringByAppendingFormat:@"+%@",addressText];
    NSString *esc_addr =  [latLng stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

        NSString *req = [NSString stringWithFormat:@"http://maps.google.com/maps/api/geocode/json?sensor=false&address=%@", esc_addr];
        NSString *result = [NSString stringWithContentsOfURL:[NSURL URLWithString:req] encoding:NSUTF8StringEncoding error:NULL];
        NSMutableDictionary *data = [NSJSONSerialization JSONObjectWithData:[result dataUsingEncoding:NSUTF8StringEncoding]options:NSJSONReadingMutableContainers error:nil];
        NSMutableArray *dataArray = (NSMutableArray *)[data valueForKey:@"results" ];
        if (dataArray.count == 0) {
            UIAlertView *alert = [[UIAlertView alloc]initWithTitle:@"Error" message:@"Please Enter a valid address" delegate:nil cancelButtonTitle:@"Ok" otherButtonTitles:nil, nil];
            [alert show];
        }else{
            for (id firstTime in dataArray) {
                NSString *jsonStr1 = [firstTime valueForKey:@"formatted_address"];
                return jsonStr1;
            }
        }

    return nil;
}

发送逗号分隔纬度经度..并尝试它的工作正常

参考链接使用iOS和iPad中的Apple功能从纬度经度获取地址