yul*_*lun 5 database laravel eloquent
我在为我的一个项目创建模式/模型时遇到问题,并希望在这里得到一些帮助.
我目前有3张桌子:配件,产品和数据透视表product_accessory
<?php
Schema::create('accessories', function(Blueprint $table)
{
$table->increments('id');
}
Schema::create('products', function(Blueprint $table)
{
$table->increments('id');
}
Schema::create('product_accessory', function(Blueprint $table)
{
$table->increments('id');
$table->integer('product_id')->unsigned();
$table->integer('accessory_id')->unsigned();
$table->foreign('product_id')->references('id')->on('products');
$table->foreign('accessory_id')->references('id')->on('accessories');
}
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现在问题是我需要添加另一种产品类型'适配器',它最终将取决于数据透视表关系,即适配器需要与产品和附件相关...
更新 以下是我当前的product_accessory_adaptor表的方式
Schema::create('product_accessory_adaptor', function(Blueprint $table)
{
$table->increments('id');
$table->integer('product_accessory_id')->unsigned();
$table->foreign('product_accessory_id')->references('id')->on('product_accessory');
}
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这样,我就可以拥有许多与产品和配件相关的适配器.我的问题是如何在雄辩中模拟这种关系?
这就是我现在拥有的:
自定义枢轴模型:
class ProductAccessory extends Pivot {
protected $table = 'product_accessory';
public function product()
{
return $this->belongsTo('Product');
}
public function accessory()
{
return $this->belongsTo('Accessory');
}
public function adaptors() {
return $this->hasMany('Adaptor', 'product_accessory_id');
}
}
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产品和附件模型
class Accessory extends Eloquent {
public function products()
{
return $this->belongsToMany('Product', 'product_accessory', 'accessory_id', 'product_id')->withPivot();
}
public function newPivot(Eloquent $parent, array $attributes, $table, $exists)
{
if ($parent instanceof Product) {
return new ProductAccessory($parent, $attributes, $table, $exists);
}
return parent::newPivot($parent, $attributes, $table, $exists);
}
public function adaptors()
{
return $this->hasManyThrough('Adaptor', 'ProductAccessory', 'accessory_id', 'product_accessory_id');
}
}
class Product extends Eloquent {
public function accessories()
{
return $this->belongsToMany('Accessory', 'product_accessory', 'product_id', 'accessory_id')->withPivot();
}
public function newPivot(Eloquent $parent, array $attributes, $table, $exists)
{
if ($parent instanceof Accessory) {
return new ProductAccessory($parent, $attributes, $table, $exists);
}
return parent::newPivot($parent, $attributes, $table, $exists);
}
public function adaptors()
{
return $this->hasManyThrough('Adaptor', 'ProductAccessory', 'product_id', 'product_accessory_id');
}
}
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适配器型号:
class Adaptor extends Eloquent {
protected $table = 'product_accessory_adaptor';
public function productAccessory() {
return $this->belongsTo('ProductAccessory');
}
}
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立即更新架构和模型已设置.但是使用hasManyThrough关系存在问题.另外,在这种情况下,对于枢轴关系,即适配器,是否有任何方法可以进行切换加载?
注意
当我在产品或附件模型上调用adapters()时发生的错误是
Argument 1 passed to Illuminate\Database\Eloquent\Relations\Pivot::__construct() must be an instance of Illuminate\Database\Eloquent\Model, none given, called in /vendor/laravel/framework/src/Illuminate/Database/Eloquent/Model.php on line 872 and defined
这是你的支点:
<?php
use Illuminate\Database\Eloquent\Model as Eloquent;
// you don't need to call it ..Pivot, just my suggestion
class ProductAccessory extends Eloquent {
protected $table = 'product_accessory';
public function product()
{
return $this->belongsTo('Product');
}
public function accessory()
{
return $this->belongsTo('Accessory');
}
public function adaptors()
{
return $this->hasMany('Adaptor', 'product_accessory_id');
}
}
// Product model
public function adaptors()
{
return $this->hasManyThrough(
'Adaptor', 'ProductAccessoryPivot', 'product_id', 'product_accessory_id'
);
}
// Accessory model
public function adaptors()
{
return $this->hasManyThrough(
'Adaptor', 'ProductAccessoryPivot', 'accessory_id', 'product_accessory_id'
);
}
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现在示例用法:
$product = Product::first();
$product->adaptors; // collection of all adaptors for given product
$product->adaptors->first()->accessory; // accessory for single adaptor
$product->accessories; // collection of accessories, each with your custom pivot, so:
$product->accessories->first()->adaptors; // collection of adaptors for given product-accessory pair
... and more, try it
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