MySQL结合UPDATE和SELECT查询

Question

我有以下返回数据的 SELECT 语句，示例如下：

SELECT performers.ID, 
       performers.Name, 
       COUNT(*) AS CountOfDeals, 
       COUNT(DISTINCT(deals.Name)) AS CountOfAliases 
  FROM deals RIGHT JOIN performers 
               ON deals.name LIKE CONCAT('%', performers.name, '%') 
 WHERE performers.ID IN ( 27952, 27951, 27950, 27949, 27948 ) 
 GROUP BY Name;

返回的数据示例：

  ID        Name             CountOfDeals     CountOfAliases
27952   Christine Hoberg          1                 0
27951   Indian Jewelry            1                 0
27952   Kinky Friedman            5                 3
27949   KJ-52                     1                 0
27960   River Whyless             1                 0

我想将其与以下 UPDATE 语句结合起来

UPDATE performers 
   SET RawAliasCount = CountOfAliases, 
       RawDealCount = CountOfDeals 
 WHERE ID = ?

运行更新语句所需的所有值都在上面的 select 语句中返回，因此希望这应该非常简单。

谢谢。

Answer 1

update与以下一起使用join：

UPDATE performers p JOIN
       (SELECT performers.ID, performers.Name, COUNT(*) AS CountOfDeals, 
               COUNT(DISTINCT(deals.Name)) AS CountOfAliases 
        FROM deals RIGHT JOIN
             performers
             on deals.name LIKE CONCAT('%', performers.name, '%') 
        WHERE performers.ID IN (27952, 27951, 27950, 27949, 27948) 
        GROUP BY Name
       ) pp
       ON pp.id = p.id
    SET RawAliasCount = pp.CountOfAliases,
        RawDealCount = pp.CountOfDeals;