Joa*_*tos 5 java swing jtextfield documentfilter
编辑 - 在帖子的最后添加了我们能够实现的答案
这是我在SO的第一篇文章,所以我希望我可以问一切正确!
尽管发布了类似的问题,我搜索并没有找到我的问题的答案,所以我希望这不是转贴.
这就是ai得到的,一个JTextField用于接收用户输入的小应用程序,除此之外我还有一个DocumentFilter用户只能输入整数和句点以便接收代表重量的值.
我的问题是,我的DocumentFilter我无法过滤"复制粘贴"文本,我无法过滤选定的文本删除.
这是Filter的代码
import javax.swing.text.AttributeSet;
import javax.swing.text.BadLocationException;
import javax.swing.text.DocumentFilter;
/**
* The Class IntAndDotFilter.
*/
public class IntAndDotFilter extends DocumentFilter {
/** The period counter. */
private int periodCounter = 0;
/** The number counter. */
private int numberCounter = 0;
private boolean canRemove = true;
public void setCanRemove(boolean canRemove) {
this.canRemove = canRemove;
}
@Override
public void replace(FilterBypass fb, int offset, int length, String text,
AttributeSet attrs) throws BadLocationException {
if (periodCounter == 0) { // If there is no . on the text
if (text.matches("\\.")) { // Checks if the input is a dot
super.replace(fb, offset, length,
text.replaceAll("[^0-9.]", ""), attrs);
periodCounter++; // If it is, inserts it and saves that info
} else {
super.replace(fb, offset, length,
text.replaceAll("[^0-9]", ""), attrs);
// If not, checks if the input is a digit
// and inserts if it is
}
} else { // If there is already a .
if (text.matches("\\.")) { // Checks if the input is another .
super.replace(fb, offset, length,
text.replaceAll("[^0-9]", ""), attrs);
// If it is, filters so that cannot be more than one .
} else {
if (text.matches("[0-9]")) { // Checks if it's a digit
if (numberCounter != 2) {
super.replace(fb, offset, length,
text.replaceAll("[^0-9]", ""), attrs);
numberCounter++;
// If yes, and if that is only the second one (0.00)
// inserts and
// saves the info that there are digits after the 1st .
// for removal purposes
} else {
super.replace(fb, offset, length,
text.replaceAll(".", ""), attrs);
// if it is the third+ digit after . , doesn't allow the
// input
}
} else {
super.replace(fb, offset, length, text.replaceAll(".", ""),
attrs);
// Not being a digit, doesn't allow the
// insertion of the given input
}
}
}
}
@Override
public void remove(FilterBypass fb, int offset, int length)
throws BadLocationException {
if (canRemove) {
if (periodCounter == 1) { // If there is a . in the text
if (numberCounter != 0) { // and If there are digits after the .
numberCounter--; // It means you'r removing a digit, so it
// saves
// that info
super.remove(fb, offset, length); // And removes it
} else { // If there are no digits it means you'r removing a .
periodCounter--; // It saves that info allowing a new . to
// be
// inserted
super.remove(fb, offset, length); // and removes it
}
} else { // If there is no . in the text there are no problems
super.remove(fb, offset, length); // so it just removes whatever
// there is (digit)
}
} else {
}
}
}
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insertString方法做了同样的替换方法,所以我把它留了出来,但在应用程序中它实现了.
在此先感谢您的时间!
编辑 - 此外它现在有一个过滤器来限制高度输入
public class IntAndDotFilter extends DocumentFilter {
/** The Constant _maxCharacters. */
private static final int _maxCharacters = 10;
/** The _is weight. */
private Boolean _isWeight = null;
public IntAndDotFilter(Boolean isWeight) {
super();
_isWeight = isWeight;
}
public void replace(FilterBypass fb, int offset, int length, String string,
AttributeSet attr) throws BadLocationException {
String text = fb.getDocument().getText(0, fb.getDocument().getLength());
text += string;
if (_isWeight) {
if ((fb.getDocument().getLength() + string.length() - length) <= _maxCharacters
&& text.matches("^[1]?[0-9]{1,2}([.][0-9]{0,2})?$")) {
super.replace(fb, offset, length, string, attr);
} else {
Toolkit.getDefaultToolkit().beep();
}
} else {
if ((fb.getDocument().getLength() + string.length() - length) <= _maxCharacters
&& text.matches("^([1]([.][0-9]{0,2})?)|([2]([.][0-5]?)?)$")) {
super.replace(fb, offset, length, string, attr);
} else {
Toolkit.getDefaultToolkit().beep();
}
}
}
@Override
public void remove(FilterBypass fb, int offset, int length)
throws BadLocationException {
String text = fb.getDocument().getText(0, fb.getDocument().getLength());
if (_isWeight) {
if (text.matches("^[1]?[0-9]{1,2}([.][0-9]{0,2})?$")) {
super.remove(fb, offset, length);
} else {
Toolkit.getDefaultToolkit().beep();
}
} else {
if (text.matches("^([1]([.][0-9]{0,2})?)|([2]([.][0-5]?)?)$")) {
super.remove(fb, offset, length);
} else {
Toolkit.getDefaultToolkit().beep();
}
}
}
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Pau*_*tha 10
你使过滤变得比以前更加复杂.对于插入(如果代码相同,则替换),您可能因为\\.检查而无法输入.您只能粘贴句点,因为这是您要检查的内容.至于删除,以下建议将适用.
为简化起见,您应该只获取文档的整个文本,然后使用正则表达式检查整个文档字符串是否与正则表达式匹配.它比你想做的要简单得多.您可以在此处获得有关过滤过程的详细说明.
这是一个例子,只使用insertString和replace.对于删除,它没有什么不同,只需获取文本,并检查它是否与正则表达式匹配.我从上面的链接中的答案中获取了部分示例.场景是OP想要最大字符,只允许一个小数位.这就是正则表达式匹配的东西.但是当你输入或插入时也可以匹配任何东西00 00. 00.0
import java.awt.GridBagLayout;
import java.awt.Toolkit;
import javax.swing.JFrame;
import javax.swing.JTextField;
import javax.swing.SwingUtilities;
import javax.swing.text.AbstractDocument;
import javax.swing.text.AttributeSet;
import javax.swing.text.BadLocationException;
import javax.swing.text.DocumentFilter;
public class FilterDemo {
public FilterDemo() {
JFrame frame = new JFrame();
frame.setLayout(new GridBagLayout());
frame.setSize(300, 300);
frame.add(createFilteredField());
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.setLocationByPlatform(true);
frame.setVisible(true);
}
public JTextField createFilteredField() {
JTextField field = new JTextField();
AbstractDocument document = (AbstractDocument) field.getDocument();
final int maxCharacters = 10;
document.setDocumentFilter(new DocumentFilter() {
public void replace(FilterBypass fb, int offs, int length,
String str, AttributeSet a) throws BadLocationException {
String text = fb.getDocument().getText(0,
fb.getDocument().getLength());
text += str;
if ((fb.getDocument().getLength() + str.length() - length) <= maxCharacters
&& text.matches("^[0-9]+[.]?[0-9]{0,1}$")) {
super.replace(fb, offs, length, str, a);
} else {
Toolkit.getDefaultToolkit().beep();
}
}
public void insertString(FilterBypass fb, int offs, String str,
AttributeSet a) throws BadLocationException {
String text = fb.getDocument().getText(0,
fb.getDocument().getLength());
text += str;
if ((fb.getDocument().getLength() + str.length()) <= maxCharacters
&& text.matches("^[0-9]+[.]?[0-9]{0,1}$")) {
super.insertString(fb, offs, str, a);
} else {
Toolkit.getDefaultToolkit().beep();
}
}
});
return field;
}
public static void main(String[] args) {
SwingUtilities.invokeLater(new Runnable() {
public void run() {
new FilterDemo();
}
});
}
}
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