Python正则表达式捕获组问题

Question

试图指定我的捕获组,但它继续捕获太多.

线:

"This is something of [Interest: stuff]. blah blah blah"

正则表达式:

patt = re.compile('\[Interest:(.){1,100}\]')

什么是输出:

[Interest: stuff]

我想要的输出:

stuff

如何输出我想要捕获的内容,而不是整个模式？

我也试过这个:

re.compile(r'\[Interest:(?P<interest>.+)\]')

那输出:

stuff]. blah blah blah

我觉得我很亲密.只需要弄清楚一旦正则表达式击中后如何停止输出]

Answer 1

该.字符匹配除换行符,包括一切].因此,(.){1,100}正在告诉Python将所有内容都放到100字符上.这包括字符串的结尾.

相反,我会使用这种模式:

\[Interest:\s([^\]]*)\]

演示:

>>> import re
>>> string = "This is something of [Interest: stuff]. blah blah blah"
>>> re.search("\[Interest:\s([^\]]*)\]", string).group(1)
'stuff'
>>>

以下是它匹配的解释:

\[         # [
Interest:  # Interest:
\s         # A space
(          # The start of a capture group
[^\]]*     # Zero or more characters that are not ]
)          # The close of the capture group
\]         # ]

有关更多信息,请参阅正则表达式语法.