b24*_*b24 13 php yii yii-extensions yii2
我有一个临时模型作为viewModel.在我的CRUD操作(例如actionCreate)中,我想获取此viewModel数据并将其分配给ActiveRecord模型.我使用下面的代码但我的模型对象atrribute总是显示属性的NULL值:
$model = new _Users();
if ($model->load(Yii::$app->request->post())) {
Yii::info($model->attributes,'test'); // NULL
$attributesValue =[
'title' => $_POST['_Users']['title'],
'type' => $_POST['_Users']['type'],
];
$model->attributes = $attributesValue;
Yii::info($model->attributes,'test'); // NULL
$dbModel = new Users();
$dbModel->title = $model->title;
$dbModel->type = $model->type . ' CYC'; // CYC is static type code
Yii::info($dbModel->attributes,'test'); // NULL
if ($dbModel->save()) {
return $this->redirect(['view', 'id' => $dbModel->id]); // Page redirect to blank page
}
}
else {
return $this->render('create', [
'model' => $model,
]);
}
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我认为$ model-> load(Yii :: $ app-> request-> post())不工作,对象属性为NULL.是Yii2错误还是我的代码不正确?
Jas*_*n G 20
如果您的属性没有规则,$model->load()则会忽略那些不在模型规则中的规则.
将属性添加到规则函数
public function rules()
{
return [
...
[['attribute_name'], 'type'],
...
];
}
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