Zom*_*ies 3 mysql sql where-clause
我有一个基本组/ avg声明:
select url, avg(contentping+tcpping), count(*) from websites ws, ping pi
where ws.idwebsite = pi.idwebsite and errortype is null
group by url order by avg(contentping+tcpping) asc;
Run Code Online (Sandbox Code Playgroud)
我现在要做的是删除任何高于平均ping 500的结果.我该怎么做......?
Eri*_*lje 13
只需添加一个having条款:
select url, avg(contentping+tcpping), count(*) from websites ws, ping pi
where ws.idwebsite = pi.idwebsite and errortype is null
group by url
having avg(contenetping+tcpping) < 500
order by avg(contentping+tcpping) asc;
Run Code Online (Sandbox Code Playgroud)