如何使用CSS选择器使用BeautifulSoup检索位于某个类中的特定链接？

Question

我是Python的新手,我正在学习它用于抓取目的我使用BeautifulSoup来收集链接(即'a'标签的href).我正在尝试收集网站http://allevents.in/lahore/的"UPCOMING EVENTS"标签下的链接.我正在使用Firebug来检查元素并获取CSS路径,但此代码没有返回任何内容.我正在寻找修复程序以及如何选择适当的CSS选择器以从任何站点检索所需链接的一些建议.我写了这段代码:

from bs4 import BeautifulSoup

import requests

url = "http://allevents.in/lahore/"

r  = requests.get(url)

data = r.text

soup = BeautifulSoup(data)
for link in soup.select( 'html body div.non-overlay.gray-trans-back div.container div.row div.span8 div#eh-1748056798.events-horizontal div.eh-container.row ul.eh-slider li.h-item div.h-meta div.title a[href]'):
    print link.get('href')

Answer 1

该页面在使用类和标记方面并不是最友好的,但即便如此,您的CSS选择器也太具体而无法在这里使用.

如果你想要即将发生的事件,你只需要第一个<div class="events-horizontal">,然后只需抓住<div class="title"><a href="..."></div>标签,所以标题上的链接:

upcoming_events_div = soup.select_one('div#events-horizontal')
for link in upcoming_events_div.select('div.title a[href]'):
    print link['href']

请注意,您应不使用r.text; 使用r.contentUnicode并将解码转换为BeautifulSoup.请参阅utf-8中的字符编码问题

Answer 2

soup.select('div')
All elements named <div>

soup.select('#author')
The element with an id attribute of author

soup.select('.notice')
All elements that use a CSS class attribute named notice

soup.select('div span')
All elements named <span> that are within an element named <div>

soup.select('div > span')
All elements named <span> that are directly within an element named <div>, with no other element in between

soup.select('input[name]')
All elements named <input> that have a name attribute with any value

soup.select('input[type="button"]')
All elements named <input> that have an attribute named type with value button

您可能也对此书感兴趣。

Answer 3

import bs4 , requests

res = requests.get("http://allevents.in/lahore/")
soup = bs4.BeautifulSoup(res.text)
for link in soup.select('a[property="schema:url"]'):
    print link.get('href')

这段代码可以正常使用!!