haskell中的点运算符

Question

我有一个使用Dot-operator的函数.现在我想写没有点.我怎样才能做到这一点？

all p = and . map p

这是正确的吗？

all p = and (map p)

我收到这些错误:

4.hs:8:13:
    Couldn't match expected type `[Bool]'
                with actual type `[a0] -> [b0]'
    In the return type of a call of `map'
    Probable cause: `map' is applied to too few arguments
    In the first argument of `and', namely `(map p)'
    In the expression: and (map p)

Answer 1

看看定义的(.):

f . g  =  \ x -> f (g x)

扩展这个给出了

and . (map p)  =  \x -> and ((map p) x)

要么

all p x  =  and (map p x)