jim*_*imj 21 sql t-sql left-join sql-server-2008
在sql server 2008中,我有以下查询:
select
c.title as categorytitle,
s.title as subcategorytitle,
i.title as itemtitle
from categories c
join subcategories s on c.categoryid = s.categoryid
left join itemcategories ic on s.subcategoryid = ic.subcategoryid
left join items i on ic.itemid = i.itemid and i.siteid = 132
where (ic.isactive = 1 or ic.isactive is null)
order by c.title, s.title
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我试图在他们的子类别中获取项目,但如果类别或子类别中没有项目,我仍然想要返回记录.永远不会返回没有项目的子类别.我究竟做错了什么?
谢谢
编辑
使用第二个左连接和where子句修改查询,但它仍然没有返回空值.:/
编辑2
将siteid移动到项目左连接.当我这样做时,我获得了比预期更多的记录.有些项目具有空的siteid,我只想在具有特定ID时包含它们.
编辑3
表结构:
Categories Table
-------
CategoryID
Title
SubCategories Table
-------
SubCategoryID
CategoryID
Title
ItemCategories Table
-------
ItemCategoryID
ItemID
SubCategoryID
IsActive
Items Table
--------
ItemID
Title
SiteID
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KM.*_*KM. 34
更改join items i...到LEFT join items i...并且您的查询应该按预期工作.
编辑
除非考虑空值,否则不能在where子句中过滤LEFT JOIN表,因为左连接允许这些列具有值,或者在没有行匹配时为空:
and i.siteid = 132 将丢弃任何具有NULL的行i.siteid,其中不存在任何行.将其移至ON:
left join items i on ic.itemid = i.itemid and i.siteid = 132
或使WHERE句柄为NULL:
WHERE ... AND (i.siteid = 132 OR i.siteid IS NULL)
编辑基于OP的编辑3
SET NOCOUNT ON
DECLARE @Categories table (CategoryID int,Title varchar(30))
INSERT @Categories VALUES (1,'Cat AAA')
INSERT @Categories VALUES (2,'Cat BBB')
INSERT @Categories VALUES (3,'Cat CCC')
DECLARE @SubCategories table (SubCategoryID int,CategoryID int,Title varchar(30))
INSERT @SubCategories VALUES (1,1,'SubCat AAA A')
INSERT @SubCategories VALUES (2,1,'SubCat AAA B')
INSERT @SubCategories VALUES (3,1,'SubCat AAA C')
INSERT @SubCategories VALUES (4,2,'SubCat BBB A')
DECLARE @ItemCategories table (ItemCategoryID int, ItemID int, SubCategoryID int, IsActive char(1))
INSERT @ItemCategories VALUES (1,1,2,'Y')
INSERT @ItemCategories VALUES (2,2,2,'Y')
INSERT @ItemCategories VALUES (3,3,2,'Y')
INSERT @ItemCategories VALUES (4,4,2,'Y')
INSERT @ItemCategories VALUES (5,7,2,'Y')
DECLARE @Items table (ItemID int, Title varchar(30), SiteID int)
INSERT @Items VALUES (1,'Item A',111)
INSERT @Items VALUES (2,'Item B',111)
INSERT @Items VALUES (3,'Item C',132)
INSERT @Items VALUES (4,'Item D',111)
INSERT @Items VALUES (5,'Item E',111)
INSERT @Items VALUES (6,'Item F',132)
INSERT @Items VALUES (7,'Item G',132)
SET NOCOUNT OFF
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我不是100%确定OP之后是什么,这将返回所有可以siteid=132在问题中给出时加入的信息
SELECT
c.title as categorytitle
,s.title as subcategorytitle
,i.title as itemtitle
--,i.itemID, ic.SubCategoryID, s.CategoryID
FROM @Items i
LEFT OUTER JOIN @ItemCategories ic ON i.ItemID=ic.ItemID
LEFT OUTER JOIN @SubCategories s ON ic.SubCategoryID=s.SubCategoryID
LEFT OUTER JOIN @Categories c ON s.CategoryID=c.CategoryID
WHERE i.siteid = 132
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OUTPUT:
categorytitle subcategorytitle itemtitle
------------------------------ ------------------------------ ------------------------------
Cat AAA SubCat AAA B Item C
NULL NULL Item F
Cat AAA SubCat AAA B Item G
(3 row(s) affected)
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这将列出所有类别,即使没有匹配 siteid=132
;WITH AllItems AS
(
SELECT
s.CategoryID, ic.SubCategoryID, ItemCategoryID, i.ItemID
,c.title AS categorytitle, s.title as subcategorytitle, i.title as itemtitle
FROM @Items i
LEFT OUTER JOIN @ItemCategories ic ON i.ItemID=ic.ItemID
LEFT OUTER JOIN @SubCategories s ON ic.SubCategoryID=s.SubCategoryID
LEFT OUTER JOIN @Categories c ON s.CategoryID=c.CategoryID
WHERE i.siteid = 132
)
SELECT
categorytitle, subcategorytitle,itemtitle
FROM AllItems
UNION
SELECT
c.Title, s.Title, null
FROM @Categories c
LEFT OUTER JOIN @SubCategories s ON c.CategoryID=s.CategoryID
LEFT OUTER JOIN @ItemCategories ic ON s.SubCategoryID=ic.SubCategoryID
LEFT OUTER JOIN AllItems i ON c.CategoryID=i.CategoryID AND s.SubCategoryID=i.SubCategoryID
WHERE i.ItemID IS NULL
ORDER BY categorytitle,subcategorytitle
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OUTPUT:
categorytitle subcategorytitle itemtitle
------------------------------ ------------------------------ ------------------------------
NULL NULL Item F
Cat AAA SubCat AAA A NULL
Cat AAA SubCat AAA B Item C
Cat AAA SubCat AAA B Item G
Cat AAA SubCat AAA C NULL
Cat BBB SubCat BBB A NULL
Cat CCC NULL NULL
(7 row(s) affected)
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i.siteid上的"WHERE"条件意味着输出中必须有"items"行.你需要写(i.siteid为空或i.siteid = 132),或者把"i.siteid = 132"到"ON"保留制度的东西,这将在itemcategories参加过工作:
select
c.title as categorytitle,
s.title as subcategorytitle,
i.title as itemtitle
from categories c
join subcategories s on c.categoryid = s.categoryid
left join itemcategories ic on s.subcategoryid = ic.subcategoryid and ic.isactive = 1
left join items i on ic.itemid = i.itemid and i.siteid = 132
order by c.title, s.title
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