输入无线电ng模型毕竟没有更新

gvl*_*lax 3 javascript radio-button angularjs

我试图解决一个难题,为什么输入[无线电]控件的ng模型没有像我期望的那样设置.加载页面时,所有无线电都会正确启动.单击不同的控件会更改radioVal变量 - 其值将在页面中呈现.

问题是看起来它只发生在DOM中.当我调试代码时,$scope.radioVal它始终是相同的......隔离的范围modalDialog不包含radioVal属性.

无线电在哪个范围内ng-model创建?它是一个不同的例子吗?


工作代码可以在jsfiddle上找到.


我的HTML代码是:

<div ng-app = "app"> 
 <div ng-controller="mainCtrl">         
   <a ng-click="showModalDlg()">Click me</a>
   <br/><br/>
   <modal-dialog show="showModal" action="actionFun">                        
    <form>
      <input type="radio" ng-model="radioVal" value="1">One<br/>
      <input type="radio" ng-model="radioVal" value="nothing changes me">Two<br/>
      <input type="radio" ng-model="radioVal" value="3">Three<br/>
          <br/><br/>
          The model changes in the DOM as expected: <b>radioVal = {{radioVal | json}}</b>
          <br/>
          but by pressing the Action button you can see that the model has not been modified. 
    </form>                        
    <a class="button" action>Action</a>                     
    </modal-dialog>
   </div>
</div>
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我的角度代码:

angular.module('common', [])
    .controller('mainCtrl', ['$scope', function($scope){

        $scope.showModal = false;
        $scope.radioVal = "nothing changes me";

        $scope.showModalDlg = function() {
           $scope.showModal = !$scope.showModal;
        };

        $scope.actionFun = function() {
           console.log('actionFun ...' + $scope.radioVal);
        };        

    }]).directive('modalDialog',
        function () {
            return {
               restrict: 'E',
               scope: {
                  show: '=',
                  action: '&',
               },
               replace: true,
               transclude: true,
               link: function (scope, element, attrs) {

                        scope.hideModal = function () {
                           scope.show = false;
                           scope.$apply();
                        };

                        $('a[hide]', element).on('click', function(){
                           scope.hideModal();
                        });

                        $('a[action]', element).on('click', function(){
                           console.log('There is no radioVal in isolated scope either ... ' + scope.radioVal);
                           scope.action()();
                           scope.hideModal();
                        });
                  },
            template: '<div class=\'ng-modal\' ng-show=\'show\'><div class=\'ng-modal-overlay\'></div><div class=\'ng-modal-dialog\' ng-style=\'dialogStyle\'><div class=\'ng-modal-dialog-content\' ng-transclude></div></div></div>'
        }
    });

  angular.module('app', ['common'])
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cha*_*tfl 5

始终把一个ng-model

您当前正在尝试将基元传递给嵌套范围,这将破坏双向绑定.如果传递一个对象,它将保持对原始对象的引用

简单地改变:

$scope.radioVal = "nothing changes me";
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至:

 $scope.myModel={radioVal : "nothing changes me"};
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并使用点 ng-model

<input  ng-model="myModel.radioVal">
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改变继承,从而改变绑定.

DEMO