Symfony2自定义事件调度程序和侦听器

Question

我正在尝试创建自定义事件,但无法使其工作.

我做了什么:

我创建了一个识别类的事件

namespace Path\ToBundle;  
final class CookieEvents
{
    const COOKIE_EVENT = 'cookie.event';
}

2.处理过的事件

namespace Path\ToBundle\EventListener;
use Path\ToBundle\Event\FilterResponseEvent;
class ResponseListener
{
    public function onCookieInit(FilterResponseEvent $event)
    {
        //some complex logic goes here
        echo('test');
    }
} 

3.created事件监听器

namespace Path\ToBundle\Event;
use Symfony\Component\EventDispatcher\Event;
use Symfony\Component\HttpFoundation\Response;
class FilterResponseEvent extends Event
{
    protected $response;
    public function __construct(Response $response)
    {
        $this->response = $response;
    }
    public function getResponse()
    {
        return $this->response;
    }
}

4.Tried在service.yml中注册事件监听器

kernel.listener.cookie.event:
    class: Path\ToBundle\Event\ResponseListener
    tags:
        - { name: kernel.event_listener, event: cookie.event, method: onCookieInit }

5.接下来我尝试在控制器动作中调度事件

//includes before class
use Symfony\Component\EventDispatcher\EventDispatcher;
use Path\ToBundle\Event\FilterResponseEvent;

//inside controller action
//... $response variable is created

$dispatcher = new EventDispatcher();
$event = new FilterResponseEvent($response);
$dispatcher->dispatch(CookieEvents::COOKIE_EVENT, $event);

return $response;
//EOF controller action

我想要实现的是能够对某些行为发起火灾事件.不幸的是,这不起作用.事件概念对我来说是新的,我对我在这里所做的事情仍然没有信心,但这是我能够从这些例子中找到的.也许有人可以告诉我,我是否会朝着正确的方向前进并纠正我？如果没有,一些指导甚至更受赞赏.

Answer 1

谢谢@Qoop 指出调度程序的正确用法：

$dispatcher = $this->get('event_dispatcher')

此外，还有命名空间错误：

class: Path\ToBundle\Event\ResponseListener  //incorrect

class: Path\ToBundle\EventListener\ResponseListener  //correct