在fortran 77中使用C++类对象

Question

有没有办法传递一个C++对象用于Fortran 77？例如:

C23456
      program main
      write (*,*) 'Hello from FORTRAN 77!'
      call readstep('cube.stp'//CHAR(0),myshape)
      stop
      end

然后使用myshape作为C++对象,它将被保存在Fortran使用的内存中,并将其传递给实际使用它的其他C++函数？

编辑:这是C++代码:

extern"C" {
    void readstep_(char*,void*);
}

void readstep_(char* inputFile, void* outShape){

    STEPControl_Reader reader;
    reader = STEPControl_Reader();

    int succeed = reader.ReadFile(inputFile);

    if(!succeed){
        std::cout << "There was an error with the input file" << std::endl;
        return;
    }

    reader.NbRootsForTransfer();
    reader.TransferRoots();

    TopoDS_Shape myShape = reader.OneShape();
    TopoDS_Shape* myShapePtr = new TopoDS_Shape();
    (*myShapePtr) = myShape;

    outShape = myShapePtr;

    return;
}

Answer 1

请阅读标签/sf/ask/tagged/fortran-iso-c-binding/的标签说明,以获得更好的选择.那里有很多问题和答案.

我将使用星形符号作为常用扩展名.

C++:

class Obj{

};

extern "C" {
  void hello_();


  void readstep_(char* name, Obj** ptr){
    *ptr = new Obj(); //use name in the actual process
  }
  void pass_it_(Obj** ptr){
    hello_();
    delete *ptr; //some usage of the object
  }

}

由于通过引用传递,它使用指向指针的指针.

FORTRAN:

  program main

    integer*8 myshape

    call readstep('cube.stp'//CHAR(0),myshape)

    call pass_it(myshape)

  end

  subroutine hello
    write (*,*) 'Hello from FORTRAN 77!'
  end subroutine

使用integer*4一个32位平台上.(注意STOP语句没有理由)

编译:

g++ f77c++.f f77c++.C -lgfortran

要么

gfortran f77c++.f f77c++.C -lstdc++

> ./a.out 
 Hello from FORTRAN 77!