tow*_*120 0 c++ templates variadic-templates c++11
为什么模板类参数在参数之后具有默认值,但在variadic之前也必须具有默认值? 实例
template<class A = int, class B, class ...Args> // B must have default argument
struct Dat{};
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另一方面,如果A没有默认参数,那么ok:
template<class A, class B, class ...Args> // B must have default argument
struct Dat{};
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这与可变参数模板无关:
template<class First, class Second> struct X {};
X<int, double> // instantiates X with First == int, Second == double
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这些参数int和double用于填充的参数First,Second由左到右.第一个参数指定第一个参数,第二个参数指定第二个参数.当参数具有默认值时,您不需要指定参数:
template<class First, class Second = double> struct X {};
X<int> // instantiates X with First == int, Second == double
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如果您现在有一个没有默认参数的第三个参数,则无法使用默认参数:
template<class First, class Second = double, class Third> struct X {};
X<int, char> // tries to instantiate X with First == int, Second == char,
// Third == ??
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模板参数包可以为空,因此它可以使用带有默认参数的参数:
template<class First, class Second = double, class... Pack> struct X {};
X<int> // instantiates X with First == int, Second == double, Pack == (empty)
X<int, char> // First == int, Second == char, Pack == (empty)
X<int, char, short, bool> // First == int, Second == char, Pack == {short, bool}
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在OP的例子中:
template<class A = int, class B, class ...Args> struct Dat {};
^~~~~~~ ^~~~~~~ ^~~~~~~~~~~~~
| | |no argument required
| |an argument IS required
|no argument required
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所以你总是要为第二个参数提供一个参数,因此,你需要为第一个参数提供一个参数.不能使用第一个参数的默认参数.