Windows shell中的"Bootstrap"python脚本没有.py/.pyw关联

Question

有时(在客户的PC中)我需要一个python脚本在Windows shell中执行,如.CMD或.BAT,但没有与PYTHON/PYTHONW关联的.py或.pyw扩展名.

我推出了一对'quick'n dirty'解决方案:

1)

"""
e:\devtool\python\python.exe %0 :: or %PYTHONPATH%\python.exe
goto eof:
""" 
# Python test
print "[works, but shows shell errors]"

2)

@echo off
for /f "skip=4 delims=xxx" %%l in (%0) do @echo %%l | e:\devtools\python\python.exe
goto :eof
::----------

# Python test
print "[works better, but is somewhat messy]"

你知道更好的解决方案吗？(即:更简洁或优雅)

---

更新:

基于@van回答,我找到了更简洁的方法(没有设置ERRORLEVEL)

@e:\devtools\python\python.exe -x "%~f0" %* & exit /b

### Python begins....
import sys

for arg in sys.argv:
    print arg

raw_input("It works!!!\n")

###

Answer 1

您可以尝试创建一个脚本是什么都python和windows shell script.在这种情况下,您可以命名为文件my_flexible_script.bat并直接或通过执行python ....

查看pylint中的pylint.bat文件内容:

@echo off
rem = """-*-Python-*- script
rem -------------------- DOS section --------------------
rem You could set PYTHONPATH or TK environment variables here
python -x "%~f0" %*
goto exit

"""
# -------------------- Python section --------------------
import sys
from pylint import lint
lint.Run(sys.argv[1:])


DosExitLabel = """
:exit
exit(ERRORLEVEL)
rem """

它与您的工作类似,但具有更多的兼容dual-script支持.