dna*_*irl 112 mysql insert-update
我正在进行插入查询,如果已经存在唯一键,则需要将大多数列更新为新值.它是这样的:
INSERT INTO lee(exp_id, created_by,
location, animal,
starttime, endtime, entct,
inact, inadur, inadist,
smlct, smldur, smldist,
larct, lardur, lardist,
emptyct, emptydur)
SELECT id, uid, t.location, t.animal, t.starttime, t.endtime, t.entct,
t.inact, t.inadur, t.inadist,
t.smlct, t.smldur, t.smldist,
t.larct, t.lardur, t.lardist,
t.emptyct, t.emptydur
FROM tmp t WHERE uid=x
ON DUPLICATE KEY UPDATE ...;
//update all fields to values from SELECT,
// except for exp_id, created_by, location, animal,
// starttime, endtime
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我不确定该UPDATE子句的语法应该是什么.我如何引用该SELECT子句中的当前行?
Mar*_*ams 159
MySQL将假定equals之前的部分引用INSERT INTO子句中指定的列,第二部分引用SELECT列.
INSERT INTO lee(exp_id, created_by, location, animal, starttime, endtime, entct,
inact, inadur, inadist,
smlct, smldur, smldist,
larct, lardur, lardist,
emptyct, emptydur)
SELECT id, uid, t.location, t.animal, t.starttime, t.endtime, t.entct,
t.inact, t.inadur, t.inadist,
t.smlct, t.smldur, t.smldist,
t.larct, t.lardur, t.lardist,
t.emptyct, t.emptydur
FROM tmp t WHERE uid=x
ON DUPLICATE KEY UPDATE entct=t.entct, inact=t.inact, ...
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iCu*_*ous 45
虽然我已经很晚了但是在为那些想要使用INSERT-SELECT查询GROUP BY条款的人看到一些合理的问题后,我想出了解决这个问题的方法.
进一步考虑马库斯亚当斯的答案和会计GROUP BY,这就是我如何通过使用来解决问题Subqueries in the FROM Clause
INSERT INTO lee(exp_id, created_by, location, animal, starttime, endtime, entct,
inact, inadur, inadist,
smlct, smldur, smldist,
larct, lardur, lardist,
emptyct, emptydur)
SELECT sb.id, uid, sb.location, sb.animal, sb.starttime, sb.endtime, sb.entct,
sb.inact, sb.inadur, sb.inadist,
sb.smlct, sb.smldur, sb.smldist,
sb.larct, sb.lardur, sb.lardist,
sb.emptyct, sb.emptydur
FROM
(SELECT id, uid, location, animal, starttime, endtime, entct,
inact, inadur, inadist,
smlct, smldur, smldist,
larct, lardur, lardist,
emptyct, emptydur
FROM tmp WHERE uid=x
GROUP BY location) as sb
ON DUPLICATE KEY UPDATE entct=sb.entct, inact=sb.inact, ...
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