将文件从Java客户端上载到HTTP服务器

Question

我想将一些文件上传到HTTP服务器.基本上我需要的是一些带有一些参数和文件的服务器POST请求.我见过只上传文件的例子,但没有找到如何传递其他参数.

这样做最简单,最自由的解决办法是什么？有没有人有我可以学习的文件上传示例？我一直在谷歌上搜索几个小时,但(也许只是其中一天)我找不到我需要的东西.最好的解决方案是不涉及任何第三方类或库的东西.

Answer 1

您通常用于java.net.URLConnection触发HTTP请求.您通常也会使用multipart/form-data编码来处理混合POST内容(二进制和字符数据).单击链接,它包含有关如何撰写multipart/form-data请求正文的信息和示例.RFC2388中更详细地描述了该规范.

这是一个启动示例:

String url = "http://example.com/upload";
String charset = "UTF-8";
String param = "value";
File textFile = new File("/path/to/file.txt");
File binaryFile = new File("/path/to/file.bin");
String boundary = Long.toHexString(System.currentTimeMillis()); // Just generate some unique random value.
String CRLF = "\r\n"; // Line separator required by multipart/form-data.

URLConnection connection = new URL(url).openConnection();
connection.setDoOutput(true);
connection.setRequestProperty("Content-Type", "multipart/form-data; boundary=" + boundary);

try (
    OutputStream output = connection.getOutputStream();
    PrintWriter writer = new PrintWriter(new OutputStreamWriter(output, charset), true);
) {
    // Send normal param.
    writer.append("--" + boundary).append(CRLF);
    writer.append("Content-Disposition: form-data; name=\"param\"").append(CRLF);
    writer.append("Content-Type: text/plain; charset=" + charset).append(CRLF);
    writer.append(CRLF).append(param).append(CRLF).flush();

    // Send text file.
    writer.append("--" + boundary).append(CRLF);
    writer.append("Content-Disposition: form-data; name=\"textFile\"; filename=\"" + textFile.getName() + "\"").append(CRLF);
    writer.append("Content-Type: text/plain; charset=" + charset).append(CRLF); // Text file itself must be saved in this charset!
    writer.append(CRLF).flush();
    Files.copy(textFile.toPath(), output);
    output.flush(); // Important before continuing with writer!
    writer.append(CRLF).flush(); // CRLF is important! It indicates end of boundary.

    // Send binary file.
    writer.append("--" + boundary).append(CRLF);
    writer.append("Content-Disposition: form-data; name=\"binaryFile\"; filename=\"" + binaryFile.getName() + "\"").append(CRLF);
    writer.append("Content-Type: " + URLConnection.guessContentTypeFromName(binaryFile.getName())).append(CRLF);
    writer.append("Content-Transfer-Encoding: binary").append(CRLF);
    writer.append(CRLF).flush();
    Files.copy(binaryFile.toPath(), output);
    output.flush(); // Important before continuing with writer!
    writer.append(CRLF).flush(); // CRLF is important! It indicates end of boundary.

    // End of multipart/form-data.
    writer.append("--" + boundary + "--").append(CRLF).flush();
}

// Request is lazily fired whenever you need to obtain information about response.
int responseCode = ((HttpURLConnection) connection).getResponseCode();
System.out.println(responseCode); // Should be 200

当您使用像Apache Commons HttpComponents Client这样的第三方库时,此代码不那么冗长.

这里错误地建议的Apache Commons FileUpload只对服务器端感兴趣.您不能在客户端使用也不需要它.

也可以看看

• 使用java.net.URLConnection来触发和处理HTTP请求

Answer 2

以下是使用Apache HttpClient的方法(此解决方案适用于那些不介意使用第三方库的人):

    HttpEntity entity = MultipartEntityBuilder.create()
                       .addPart("file", new FileBody(file))
                       .build();

    HttpPost request = new HttpPost(url);
    request.setEntity(entity);

    HttpClient client = HttpClientBuilder.create().build();
    HttpResponse response = client.execute(request);

Answer 3

单击链接获取示例文件，使用apache HttpComponents上传clint java

http://hc.apache.org/httpcomponents-client-ga/httpmime/examples/org/apache/http/examples/entity/mime/ClientMultipartFormPost.java

和图书馆downalod链接

https://hc.apache.org/downloads.cgi

使用4.5.3.zip在我的代码中工作正常

和我的工作代码

import java.io.File;
import org.apache.http.HttpEntity;
import org.apache.http.client.methods.CloseableHttpResponse;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.ContentType;
import org.apache.http.entity.mime.MultipartEntityBuilder;
import org.apache.http.entity.mime.content.FileBody;
import org.apache.http.entity.mime.content.StringBody;
import org.apache.http.impl.client.CloseableHttpClient;
import org.apache.http.impl.client.HttpClients;
import org.apache.http.util.EntityUtils;

public class ClientMultipartFormPost {

     public static void main(String[] args) throws Exception {

          CloseableHttpClient httpclient = HttpClients.createDefault();
          try {
             HttpPost httppost = new HttpPost("http://localhost:8080/MyWebSite1/UploadDownloadFileServlet");

             FileBody bin = new FileBody(new File("E:\\meter.jpg"));
             StringBody comment = new StringBody("A binary file of some kind", ContentType.TEXT_PLAIN);

             HttpEntity reqEntity = MultipartEntityBuilder.create()
                .addPart("bin", bin)
                .addPart("comment", comment)
                .build();


             httppost.setEntity(reqEntity);

             System.out.println("executing request " + httppost.getRequestLine());
             CloseableHttpResponse response = httpclient.execute(httppost);
           try {
                System.out.println("----------------------------------------");
                System.out.println(response.getStatusLine());
                HttpEntity resEntity = response.getEntity();
                if (resEntity != null) {
                     System.out.println("Response content length: " +    resEntity.getContentLength());
                }
              EntityUtils.consume(resEntity);
             } finally {
                 response.close();
            }
       } finally {
          httpclient.close();
      }
   }

}